Answer:
the answer I take was 213+42.15=255.15 je have on each
What we have here is a problem of proportions. We're assuming that the probabilities - the ratio of rainy days to total days - are equal; 3 is to 20 as <em>something</em> (let's call it <em>r </em>for "rainy days") is to 365. Mathematically, that gives us this equality:
![\frac{3}{20}= \frac{r}{365}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B20%7D%3D%20%5Cfrac%7Br%7D%7B365%7D%20)
To solve for <em>r</em>, we can simply multiply either side of the equation by 365:
![(365) \frac{3}{20} = \frac{r}{365}(365)\\\\ \frac{365\cdot3}{20}=r](https://tex.z-dn.net/?f=%28365%29%20%5Cfrac%7B3%7D%7B20%7D%20%3D%20%5Cfrac%7Br%7D%7B365%7D%28365%29%5C%5C%5C%5C%20%5Cfrac%7B365%5Ccdot3%7D%7B20%7D%3Dr%20)
365 and 20 have the factor 5 in common, so we can use that to reduce the fraction to:
![r= \frac{73\cdot3}{4}= \frac{219}{4} = 54 \frac{3}{4}](https://tex.z-dn.net/?f=r%3D%20%5Cfrac%7B73%5Ccdot3%7D%7B4%7D%3D%20%5Cfrac%7B219%7D%7B4%7D%20%3D%2054%20%5Cfrac%7B3%7D%7B4%7D%20)
So, the number of rainy days, if that pattern continued, would be around 54 3/4 days, or
55, rounded up to the nearest day.
Answer:
n = 20
Step-by-step explanation:
4n + 14 - 5n = -6
(4n - 5n) + 14 = -6 Combine like terms
-n + 14 = -6
-14 -14 Subtract 14 from both sides
-n = -20
/-1 /-1 Divide by -1
n = 20
Answer:b
Step-by-step explanation:
Step-by-step explanation:
5x + 3y ≥ -3
5x ≥ -3
x ≥ -3/5
5x + 3y ≥ -3
3y ≥ -3
y ≥ -3/3
y ≥ -1
Solution
x ≥ -3/5 and y ≥ -1