Recall that variation of parameters is used to solve second-order ODEs of the form
<em>y''(t)</em> + <em>p(t)</em> <em>y'(t)</em> + <em>q(t)</em> <em>y(t)</em> = <em>f(t)</em>
so the first thing you need to do is divide both sides of your equation by <em>t</em> :
<em>y''</em> + (2<em>t</em> - 1)/<em>t</em> <em>y'</em> - 2/<em>t</em> <em>y</em> = 7<em>t</em>
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You're looking for a solution of the form

where


and <em>W</em> denotes the Wronskian determinant.
Compute the Wronskian:

Then


The general solution to the ODE is

which simplifies somewhat to


=

Multiply both sides by 12, so that we get rid of the fraction in x.
12 · (x+3)/12 = 2/7 · 12
Simplify.
x + 3 = 24/7
Then, subtract 3 from both sides, so that "x" gets isolated.
x = 24/7 - 3
Turn "3" into an improper fraction so that we could find the value of x easier.
3 = 21/3
So :
x = 24/7 - 21/7
Simplify.
x = 3/7
~Hope this helps!~
A system of equations for this would be
19x + 11y = 273
and
12x + 17y = 283.
X is the amount of minutes to solve one long division problem and y is the amount of minutes to solve a graphing problem.
How To Solve This System of Equations.
Multiply both by 17 and 11 respectively for them to have the greatest common factor for y. So now both equations are:
323x + 187y= 4641
132x + 187y= 3113.
Subtract both equations and you have left:
191x = 1528.
Divide both sides by 191 and you find x.
X = 8.
Answer
It takes Sally 8 minutes to do one Long Division Problem.
Hope this helped. ;)
Answer:
249 centimeters squared
Step-by-step Explanation:
The area of the rectangle: l x w, where l is the length and w is the width.
= 15.5 x 18
= 279
Area of the smaller rectangle: l x w, where l is the length and w is the width.
= 4 x 7.5
= 30
We do not need this 30.
Area of the shaded region:
= 279 - 30
= 249 cm²