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Sedaia [141]
3 years ago
11

Can someone tell me how to solve this? 24fgtrgbbfgb3⁴528ujhjh69hhgyy • 34hjmnbfvff678fghygrrdcssa

Mathematics
1 answer:
arsen [322]3 years ago
6 0

Answer:

1632630422016g^6tr^3b^3uj^3h^5y^3mnf^4g^2r^2dcs^2a

Step-by-step explanation:

First simplify each thing:

24fgtrgbbfgb3⁴528ujhjh69hhgyy = 70823808g^4trb^3uj^2h^4y^2

34hjmnbfvff678fghygrrdcssa = 23052h^2jmnbf^4g^2hygr^2dcs^2a

Multiply them: 1632630422016g^6tr^3b^3uj^3h^5y^3mnf^4g^2r^2dcs^2a

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3 years ago
The bearing of Q from P is 150
Lynna [10]

Answer:

(i) see first attached diagram

(ii) QR = 22.67 km (2 dp)

(iii) 243°

Step-by-step explanation:

A bearing is the angle in degrees measured clockwise from north.

<u />

<u>Part (i)</u>

see first attached diagram

<u>Part (ii)</u>

The angles marked in blue on the second attached diagram are Consecutive Interior Angles.  In this case they add to 180° as the North lines are parallel.

The sum of angles around a point is 360°

⇒ m∠QPR (shown in red on the second attached diagram) = 360 - 150 - (180 - 15) = 45°        

To calculate the distance between Q and R (marked in red on the attached diagram), use the cosine rule.

⇒ QR² = PR² + QP² - 2(PR)(QP)cos(QPR)

⇒ QR² = 32² + 24² - 2(32)(24)cos(45)

⇒ QR² = 513.8839841...

⇒ QR = √513.8839841...

⇒ QR = 22.67 km (2 dp)

<u>Part (iii)</u>

We need to find the angle marked in green on the third attached diagram.

To do this, we need to find the angle marked in pink and the angle marked in orange, then subtract them from 360°

Pink angle = 180 - 150 = 30° (using the same consecutive angle theorem as before)

Orange angle (o) using the sine rule:

⇒ sin(o)/32 = sin(45)/QR

⇒ sin(o) = 32sin(45)/22.67

⇒ sin(o) = 0.9981652337...

⇒ o = 86.52868176...°

Therefore, the green angle = 360 - 30 - 86.52868176... = 243° (nearest degree)

8 0
2 years ago
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