Can someone tell me how to solve this? 24fgtrgbbfgb3⁴528ujhjh69hhgyy • 34hjmnbfvff678fghygrrdcssa

Mathematics

1 answer:

arsen [322]3 years ago

6 0

Answer:

$1632630422016g^6tr^3b^3uj^3h^5y^3mnf^4g^2r^2dcs^2a$

Step-by-step explanation:

First simplify each thing:

24fgtrgbbfgb3⁴528ujhjh69hhgyy = $70823808g^4trb^3uj^2h^4y^2$

34hjmnbfvff678fghygrrdcssa = $23052h^2jmnbf^4g^2hygr^2dcs^2a$

Multiply them: $1632630422016g^6tr^3b^3uj^3h^5y^3mnf^4g^2r^2dcs^2a$

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The monthly salary of workers in the public works department is $1,500, $3,000, $3,500, $3,500, $4,000, $4,500, $5,000, $6,000,

adelina 88 [10]

Answer:

(B) median because there is an outlier

Step-by-step explanation:

The given data is as follows:

{1, 4, 9, 4, 10, 8, 42}

We can see from the given data that 42 is a data point which differ greatly from the other data points, and from the definition of OUTLIER that is a data point that differ greatly from the trend expressed by the other values in the data set.

Thus, 42 is an outlier.

Now, We have to find the center for the given data set, thus we will use the median as the definition of median states that median is the middle value of the data set.

Therefore, the best measure to find the center of the given data will be median because there is an outlier 42 present in it.

Thus, option B is correct.

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Step-by-step explanation:

3 0

3 years ago

Simplify the expression 1/√(1-cos^2 x) . Remember cos x= 1/csc x

Cerrena [4.2K]

First, we are going to use the Pythagorean identity: $sin^2(x)+cos^2(x)=1$ to rewrite our expression. Solving for $sin^2(x)$ in our Pythagorean identity we get that $sin^2(x)=1-cos^2(x)$ , so we can rewrite our expression as follows:
$\frac{1}{ \sqrt{1-cos^2(x)} } = \frac{1}{ \sqrt{sin^2(x)} } = \frac{1}{sin(x)}$

Next, we are going to use the trig identity: $csc(x)= \frac{1}{sin(x)}$ to completely simplify our expression:
$\frac{1}{sin(x)} =csc(x)$

We can conclude that $\frac{1}{ \sqrt{1-cos^2(x)} }=csc(x)$