This is what I got RR || SS
Tossing a die will have 6 possible outcomes. Those are having sides that are number 1 to 6. The sample space of tossing 3 dice is equal to 6³ which is equal to 216. Now for the calculation of probabilities,
P(two 5s) = (1 x 1 x 5)/216
As we have to have the 5 in the die for two times, then for the 1 time, we can have all other numbers except 5. The answer is 5/216.
P(three 5s) = (1 x 1 x 1)/216 = 1/216
P(one 5 or two 5s) = (1 x 5 x 5)/216 + (1 x 1 x 5)/216 = 5/36
upto four roots or zero......
Answer:
$76 x 1.20 = $92
$92 / 1.20 = $76
To keep and show decimals we divide 20 by 100 to show 1.02 then show any 2 placement decimals if none are shown in draft first then you can try in draft 20/1000 to see the difference between the decimals.
Step-by-step explanation:
Answer:
40+39=79
Step-by-step explanation:
10 times 4+30+9
40*39=79
