Question

What is the product?

Answer 1

Answer:

The answer is D

Step-by-step explanation:

Answer 2

Answer:

$\frac{4k + 2}{k^{2}-4 }$  ×  $\frac{k-2}{2k+1}$   =  $\frac{2}{k + 2}$

Step-by-step explanation:

$\frac{4k + 2}{k^{2}-4 }$  ×  $\frac{k-2}{2k+1}$

To solve the above, we need to follow the steps below;

4k+2 can be factorize, so that;

4k +2 = 2 (2k + 1)

k² - 4  can also be be expanded, so that;

k² - 4 = (k-2)(k+2)

Lets replace  4k +2  by  2 (2k + 1)

and

k² - 4 by  (k-2)(k+2)   in the expression  given

$\frac{4k + 2}{k^{2}-4 }$  ×  $\frac{k-2}{2k+1}$

$\frac{2(2k+ 1)}{(k-2)(k+2)}$   ×  $\frac{k-2}{2k+1}$

(2k+1) at the numerator will cancel-out (2k+1) at the denominator, also (k-2) at the numerator will cancel-out (k-2) at the denominator,

So our expression becomes;  

$\frac{2}{k + 2}$

Therefore, $\frac{4k + 2}{k^{2}-4 }$  ×  $\frac{k-2}{2k+1}$   =  $\frac{2}{k + 2}$