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slamgirl [31]
2 years ago
13

one strand of lights for a Christmas tree 250 light bulbs. If 20% of the light bulbs are green how many light bulbs on the stran

d of light are green?
Mathematics
1 answer:
Nadusha1986 [10]2 years ago
6 0

Answer:

20% of 250 is 50

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The volume of a sphere is 904.32 cm3, find its radius and hence its curved surface area​
Harlamova29_29 [7]

Volume = \frac{4}{3} * π * r³ = 904.32 cm³

radius = \sqrt[3]{\frac{3*Volume}{4 * pi} } cm=

= \sqrt[3]{\frac{3 * 904.32}{4 * 3.14} } cm=

= \sqrt[3]{\frac{2712,96}{12.56} } cm=

= \sqrt[3]{216} cm=

radius = 6 cm

surface = 4 * π * r² cm² =

= 4 * π * 6² cm² =

= 4 * 3.14 * 36 cm² =

=  452,16 cm²

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3 years ago
If y+36=102, then y+14=<br><br>A) 66<br>B) 76<br>C) 80<br>D) 124
Len [333]
The answer is C since we can solve for y in the first equation by subtracting 36 on both sides which gives us 66. Therefore we know that y= 66 and can plug it into the following equation which is 66+14 = 80
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Angle 1 and 2 are supplementary. Angle 1=3x° angle 2=(2x. -25)° select from the drop down menu
goldfiish [28.3K]

Answer:

x = 41°

∠1 = 123°

∠2 = 57°

Step-by-step explanation:

If angles 1 & 2 are supplementary, that means...

\angle1 +\angle2=180\textdegree

To find the value of each angle, you first must find the value of x by plugging in the values of both angles...

\angle1 +\angle2=180\textdegree\Longrightarrow3x+(2x - 25) = 180\textdegree

First, combine like values, then subtract add 25 to both sides.

3x + 2x = 5x\Longrightarrow 5x - 25+ (25) = 180 + (25)\\\\5x=205

Then, divide both sides by 5, and plug the value of x into the original equations for angles 1 & 2.

\frac{5x = 205}{5}\\\\x = 41\textdegree\\\\\angle1= 3x = 3(41) = 123\textdegree\\\\\angle2=2x-25=2(41)-25=82-25=57\textdegree

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garri49 [273]

Answer:

12 is the best answer

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What is the inverse of f(x)=3x-1
tatiyna

Answer:

$ \frac{(y + 1)}{3} $

Step-by-step explanation:

Call $ f(x) = y = 3x - 1 $

Now, $ y + 1 = 3x $

$ \implies \frac{y + 1}{3} = x $

This is the inverse of the given function.

You can cross - verify it by substituting a point, say, $ (1,3) $

We see that the point satisfies both the equations.

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