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GuDViN [60]
2 years ago
12

In how many ways can you arrange six trophies on a shelf?

Mathematics
1 answer:
melisa1 [442]2 years ago
7 0

Answer:

720 ways

Step-by-step explanation:

Assuming order doesn't matter, there are 6!=6*5*4*3*2*1=720 ways to arrange six trophies on a shelf.

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We buy these products for $50.00 and then sell them for $67.00. That means that our price markup is?
Gekata [30.6K]

That means our price markup is $67.00-$50.00=$17.00

3 0
2 years ago
Emily made 75% of the basket that she attempted if she made 9 baskets how many attempts did she make
quester [9]

Emily made 9 baskets out of the 12 attempts.

7 0
2 years ago
Read 2 more answers
I need help on my homework
soldi70 [24.7K]

Answer:

\displaystyle m\angle AED=32.5^\circ

Step-by-step explanation:

<u>Angles in a Circle</u>

An exterior angle of a circle is an angle whose vertex is outside a circle and the sides of the angle are secants or tangents of the circle.

Segments AE and DE are secants of the given circle. They form an exterior angle called AED.

The measure of an exterior angle is equal to half the difference of the measure of their intercepted arcs.

Intercepted arcs in the given circle are AD=113° and BC=48°. The exterior angle is:

\displaystyle m\angle AED=\frac{AD-BC}{2}

\displaystyle m\angle AED=\frac{113^\circ-48^\circ}{2}=\frac{65^\circ}{2}

\displaystyle m\angle AED=32.5^\circ

8 0
2 years ago
In the equation y = kx, the slope of the line is represented by the constant
vovangra [49]
K is the constant of proportionality also the same as slope.
You can see the commonality in the equations
y = kx
y = mx + b
The difference is that is a direct proportion the line will always go through the origin so the b will be zero.
The answer is B.
7 0
3 years ago
Solve the system of equations. y=23x–19 x2–y= – 6x–23 Write the coordinates as integers, simplified proper or improper fractions
forsale [732]

Answer:

(3, 50) and (14,303)

Step-by-step explanation:

Given the system of equations;

y=23x–19 ....1

x²–y= – 6x–23 ...2

Substitute 1 into 2;

x²–(23x-19)= – 6x–23

x²–23x+19= – 6x–23 .

x²-23x + 6x + 19 + 23  = 0

x² - 17x + 42 = 0

Factorize;

x² - 14x - 3x + 42 = 0

x(x-14)-3(x-14) = 0

(x-3)(x-14) = 0

x = 3 and 14

If x = 3

y = 23(3) - 19

y = 69-19

y = 50

If x = 14

y = 23(14) - 19

y = 322-19

y = 303

Hence the coordinate solutions are (3, 50) and (14,303)

8 0
3 years ago
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