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Deffense [45]
3 years ago
6

Which represents the solution(s) of the system of equations, y = x2 – x + 1 and y = x? Determine the solution set by graphing.

Mathematics
2 answers:
Liula [17]3 years ago
8 0

Answer:

(1,1)

Step-by-step explanation:

we have

y=x^{2}-x+1 -------> equation A

y=x -------> equation B

we know that

The solution of the system of equations is the intersection points both graphs

using a graphing tool

see the attached figure

The intersection both graphs is the point (1,1)

therefore

the solution is the point (1,1)

natali 33 [55]3 years ago
7 0
Hello,

sol={(1,1)}

Answer A

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The total cost of 7 shirts and 5 pairs of pants is $517. The total cost of a shirt and a pair of pants is $89. How much does a p
pickupchik [31]

Answer:

pair of pants = $53

Step-by-step explanation:

s = shirts

p = pair of pants

eq = equation

eq 1:          7s + 5p = 517

eq 2:           s + p = 89

multiply the equation 2 by 7

eq 3:        7s + 7p = 623

negate equation 1 and add it to the eq 3

      7s + 7p = 623

+    -7s - 5p = -517

             2p = 106

               p = 53

7 0
2 years ago
An equivalent equation for 4x+11=15​
Keith_Richards [23]

Answer:I can solve it?

take away 11 from both sides to make..

4x = 4

simplified (4 ÷ 4) to make x=1

Step-by-step explanation:

4 0
4 years ago
Mr.o'brien is paid $7.30 per hour for the first 40 hours he works in a week.He is paid 1.5 times that rate for each hour after t
zalisa [80]
In first 40 hours he earns = 7.30 x 40 = $292
Each hour after his rate = 7.20 x 1.5 = $10.80 per hour
In extra four hours he earns = 10.80 x 4 =  $43.20 

Total earnings = $292 + $43.20 = $335.20 
Therefore you don't agree 
7 0
4 years ago
I would like some help thank you :)
pantera1 [17]

Answer:

\angle AE = 32^{\circ}

\angle EAD = 212^{\circ}

\angle BE = 133^{\circ}

\angle BCE = 227^{\circ}

\angle AED = 180^{\circ}

\angle BD = 79^{\circ}

Step-by-step explanation:

The central angle of a circle is equal to 360º, whose formula in this case is:

\angle AB + \angle BC + \angle CD + \angle DE + \angle EA = 360^{\circ}

In addition, the following conditions are known from figure:

\angle BC = 47^{\circ}, \angle DE = 148^{\circ}

\angle DE + \angle EA = 180^{\circ}

\angle CD + \angle DE = 180^{\circ}

\angle AB + \angle BC + \angle CD = 180^{\circ}

Now, the system of equations is now solved:

\angle EA = 180^{\circ}-\angle DE

\angle EA = 180^{\circ}-148^{\circ}

\angle EA = 32^{\circ}

\angle CD = 180^{\circ}-\angle DE

\angle CD = 180^{\circ}-148^{\circ}

\angle CD = 32^{\circ}

\angle AB = 180^{\circ} - \angle BC - \angle CD

\angle AB = 180^{\circ}-47^{\circ}-32^{\circ}

\angle AB = 101^{\circ}

The answers are described herein:

\angle AE = 32^{\circ}

\angle EAD = 212^{\circ}

\angle BE = 133^{\circ}

\angle BCE = 227^{\circ}

\angle AED = 180^{\circ}

\angle BD = 79^{\circ}

7 0
3 years ago
Hi what is theanswer
USPshnik [31]

Answer:

540

Step-by-step explanation:

6 0
4 years ago
Read 2 more answers
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