All categories

3 years ago

Please help me out :)

Mathematics

1 answer:

Drupady [299]3 years ago

6 0

180-124=56

56/2=28

Ans 28

You might be interested in

What is the value of h(−2) when h(x)=3x+1

adell [148]

Replace x with -2 in the equation and solve.

3(-2) +1 = -6 + 1 = -5

5 0

3 years ago

Read 2 more answers

What value of p makes the equation true?

cluponka [151]

Answer:

p = 1/8

Step-by-step explanation:

-3p + 1/8 = -1/4

-3p = -1/8 -14 /*8

-24p = -1 -2

-24p = -3 /:(-24)

p = 1/8

7 0

3 years ago

Help me plssssssssss

Lera25 [3.4K]

Pretty sure it’s d(all of the above)

3 0

3 years ago

Simplify 7 ∙ 6 ∙ 2h ∙ d.

tekilochka [14]

(7)(6)(2h)(d)
(42)(2h)(d)
(84h)(d)
84hd

6 0

3 years ago

Read 2 more answers

Find the period.

Andre45 [30]

Answer:

The Time period of the Amount is 5 years 3 days .

Step-by-step explanation:

Given as :

The principal = p = Rs 9300

The annual rate of interest = r = 13%

The Total amount after t years = A = Rs 17,763

Let The time period = t years

From Compound Interest method

Amount = principal × $(1+\dfrac{\textrm rate}{100})^{\textrm time}$

Or, A = p × $(1+\dfrac{\textrm r}{100})^{\textrm t}$

Or, Rs 17,763 = Rs 9300 × $(1+\dfrac{\textrm 13}{100})^{\textrm t}$

Or, $\dfrac{17763}{9300}$ = $(1.13)^{t}$

or, 1.91 = $(1.13)^{t}$

Taking Log both side

$Log_{10}$ 1.91 = $Log_{10}$ ( $(1.13)^{t}$ )

or, 0.2810 = t × $Log_{10}$ 1.13

or, 0.2810 = t × 0.0530

∴ t - $\dfrac{0.2810}{0.0530}$

I.e t = 5.30 years

So, The time period = t = 5 years 3 days

Hence The Time period of the Amount is 5 years 3 days . Answer

6 0

3 years ago