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iren [92.7K]
3 years ago
10

Using the quadratic formula to solve 11x^2-4x=1 what are the values of x ?

Mathematics
1 answer:
Kaylis [27]3 years ago
8 0

The answer should be the 1st one.

Just use the quadratic formula and plug in the necessary numbers when requested and work from there.

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Hello:) anyone able to help with this question ? Thank you!
svetlana [45]

Answer:

look at the photo below for the Answer.

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6 0
4 years ago
Read 2 more answers
If a=5x^2+3x-7 and b=-3x^2-7x+5 find b-a
uranmaximum [27]

Answer:

-8x^2-10x+12

Step-by-step explanation:

first set up the problem:

(-3x^2-7x+5)-(5x^2+3x-7)

Since you are subtracting you need to distribute the (-) sign:

(-3x^2‐7x+5)(-5x^2-3x+7)

Now just combine like terms

-3x^2+(-5x^2= -8x^2

(-7x+(-3x= -10x

5+7= 12

set answer in standard form:

-8x^2-10x+12

3 0
3 years ago
How do you end up with 0=0
Eva8 [605]
Ok so first plug in y for in the equation 2x-2y=12
Therefore 2x - 2(x -6)=12
Then distribute the two to the x and the -6 
2x-2x+12=12
The 2x's cancel leaving you with 
12=12
From there you could subtract the 12 from both sides to get 0=0, I assume
4 0
3 years ago
Read 2 more answers
Calculate the axis of symmetry in the equation Y = (x+1) (x-4)
algol [13]

Answer:

<em>Every </em><em>parabola </em><em>has </em><em>a </em><em>turning</em><em> point</em><em> </em><em>called </em><em>the </em><em>axis</em><em> of</em><em> symmetry</em><em>,</em><em>so </em><em>for </em><em>this </em><em>question</em><em> </em><em>you </em><em>just</em><em> </em><em>have </em><em>to </em><em>find </em><em>the </em><em>turning</em><em> </em><em>points</em>

<em>x </em><em>turning</em><em> </em><em>point</em><em>=</em><em> </em><em>-b/</em><em>2</em><em>a</em><em>,</em><em>and </em><em>the </em><em>y </em><em>turning</em><em> </em><em>point</em><em> </em><em>is </em><em>gotten</em><em> </em><em>by </em><em>replacing</em><em> </em><em>the </em><em>value </em><em>of </em><em>x </em><em>in </em><em>the </em><em>equation</em>

<em>y=</em><em>(</em><em>x+</em><em>1</em><em>)</em><em>(</em><em>x-4)</em>

<em> </em><em> </em><em>=</em><em>x^</em><em>2</em><em>-</em><em>3</em><em>x</em><em>-</em><em>4</em>

<em>a </em><em>is </em><em>1</em><em>,</em><em>b </em><em>is </em><em>-</em><em>3</em><em> </em><em>and </em><em>c </em><em>is </em><em>-</em><em>4</em>

<em>x=</em><em> </em><em>-</em><em>(</em><em>-</em><em>3</em><em>)</em><em>/</em><em>2</em><em>(</em><em>1</em><em>)</em>

<em> </em><em> </em><em>=</em><em>1</em><em>.</em><em>5</em>

<em>and </em><em>y=</em><em>x^</em><em>2</em><em>-</em><em>3</em><em>x</em><em>-</em><em>4</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>1</em><em>.</em><em>5</em><em>^</em><em>2</em><em>-</em><em>3</em><em>(</em><em>1</em><em>.</em><em>5</em><em>)</em><em>-</em><em>4</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>-</em><em>6</em><em>.</em><em>2</em><em>5</em>

<em>therefore</em><em> </em><em>the </em><em>axis </em><em>of</em><em> symmetry</em><em> is</em><em> (</em><em>1</em><em>.</em><em>5</em><em>,</em><em>-</em><em>6</em><em>.</em><em>2</em><em>5</em><em>)</em>

<em>I </em><em>hope </em><em>this </em><em>helps</em>

6 0
3 years ago
Please please give answer for this question
Delvig [45]
ANSWER: 25

EXPLANATION: First find the area of one single square by multiplying b(BASE) * h(HEIGHT). Repeat for other figure. Finally you will add both sums.
5 0
3 years ago
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