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olasank [31]
3 years ago
15

Mr smith has 1,104 student photos to display around the school. He plans to put them on 48 posters boards with the same number o

f photos on each poster board how many were in each poster board
Mathematics
1 answer:
-BARSIC- [3]3 years ago
4 0
There will be 23 student photo’s on 48 poster boards. All you have to do is divide 1,104 with 48
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Identify the diameter of the circular base created by folding the figure into a right cone. HELP ASAP PLEASE!!
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let's notice something, we have a circle with a radius of 12 and one 90° sector is cut off, so only three 90° sectors of the circle are left shaded, so namely the cone will be using 3/4 of that circle.

think of it as, this shaded area is some piece of paper, and you need to pull it upwards and have the cutoff edges meet, and when that happens, you'll end up with a cone-shaped paper cup, and pour in some punch.

now, once we have pulled up the center of the circle to make our paper cup, there will be a circular base, its diameter not going to be 24, it'll be less, but whatever that base is, we know that is going to have the same circumference as those in the shaded area.  Well, what is the circumference of that shaded area?

\bf \textit{circumference of a circle}\\\\ C=2\pi r~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=12 \end{cases}\implies C=2\pi 12\implies C=24\pi \implies \stackrel{\textit{three quarters of it}}{24\pi \cdot \cfrac{3}{4}} \\\\\\ 6\pi \cdot 3\implies 18\pi

well then, the circumference of that circle at the bottom will be 18π, so, what is the diameter of a circle with a circumferenc of 18π?

\bf \textit{circumference of a circle}\\\\ C=2\pi r~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ C=18\pi \end{cases}\implies 18\pi =2\pi r\implies \cfrac{18\pi }{2\pi }=r\implies 9=r \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{\textit{diameter is twice the radius}}{d=18}~\hfill

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A department store sells small boxes in which customers can store potpourri. The diagram below shows one of the boxes. The diagr
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The lateral area is expressed as the product of the perimeter of the base and the height. While the surface area is the sum of all areas. The lateral area and the surface area of the box is calculated as follows:

LA = Ph 
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SA = 2(lw + wh + lh)
SA = 2[(17x5) + (5x3.12) + (17x3.12)]
SA = 307.28 cm

Thus, the lateral area and the surface area are 137 cm and 307 cm, respectively.
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