Answer:
The equivalent percentage point drop = 10%
Step-by-step explanation:
The percentage point change is the difference between the final and initial values.
The percentage change is the difference between the final and initial values
divided by the initial value
It is required to decrease the dropout rate from 30% to 20%
The point change = 20 - 30 = -10 (-ve change ⇒ decrease)
The percentage change = 
%
So, the equivalent percentage point drop = <u>10%</u>
And the percentage change = <u>33.33%</u>
For this case, the first thing we must do is take into account the definition of the axes:
the x axis is time in seconds
the y axis is velocity in meters per secon
Then, we look for the cut point with the y axis, which is given by:
(0, 2)
This means that the initial speed is 2 m / s.
We now look for the cut point with the x axis, which is given by:
(8, 0)
This means that the speed is 0 m / s, so the runner stopped when the time is 8 seconds.
Answer:
The initial velocity of the runner was 2 m / s, and the runner stopped after 8 seconds.
If you have two vectors A and B,
Dot product is a scalar quantity dealing with how much of one vector is in the same direction as the other vector, or the projection of one onto the other. You can see that from the cosine part of this form-
![A~*~B = [A][B]cos(\theta)](https://tex.z-dn.net/?f=A~%2A~B%20%3D%20%5BA%5D%5BB%5Dcos%28%5Ctheta%29)
The cross product is a vector perpendicular to both A and B. It deals with how much of one vector is perpendicular to the other vector. You can see that in the sine part of this form -
![A ~x ~B= [A][B]sin(\theta)](https://tex.z-dn.net/?f=A%20~x%20~B%3D%20%5BA%5D%5BB%5Dsin%28%5Ctheta%29)
Answer:
5 1/3
Step-by-step explanation:
I caculated 2/3 times 8
