Answer:
585 cars
Step-by-step explanation:
Given

per floor
Required
Determine the total number of cars
This is calculated by multiplying number of cars per floor by number of floors.



<em>Hence, there are 585 cars in total</em>
6y-4=4y+2
2y=6, so y=3.
Plugging it in, you get that AC equals 4*3+2=14.
This is an isosceles triangle.
Answer:
Vinay jumped = 49m
Step-by-step explanation:
Given:
Shubham jumped = 41m
Ashish jumped = 3m less than Shubham
Vinay jumped = 11m more than Ashish
Find:
Length of Viney's jump
Computation:
Ashish jumped = Shubham jumped - 3m
Ashish jumped = 41m - 3m
Ashish jumped = 38m
Vinay jumped = Ashish jumped + 11m
Vinay jumped = 38m + 11m
Vinay jumped = 49m
Answer:
Step-by-step explanation:
Given
radius of wheel 
Time period of Wheel 
and
, where 

Let at any angle
with vertical position of a point is given by


and 
for velocity differentiate x and y to get


Height at any time t is given by

Answer:
In a certain Algebra 2 class of 30 students, 22 of them play basketball and 18 of them play baseball. There are 3 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?
I know how to calculate the probability of students play both basketball and baseball which is 1330 because 22+18+3=43 and 43−30 will give you the number of students plays both sports.
But how would you find the probability using the formula P(A∩B)=P(A)×p(B)?
Thank you for all of the help.
That formula only works if events A (play basketball) and B (play baseball) are independent, but they are not in this case, since out of the 18 players that play baseball, 13 play basketball, and hence P(A|B)=1318<2230=P(A) (in other words: one who plays basketball is less likely to play basketball as well in comparison to someone who does not play baseball, i.e. playing baseball and playing basketball are negatively (or inversely) correlated)
So: the two events are not independent, and so that formula doesn't work.
Fortunately, a formula that does work (always!) is:
P(A∪B)=P(A)+P(B)−P(A∩B)
Hence:
P(A∩B)=P(A)+P(B)−P(A∪B)=2230+1830−2730=1330