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Gnoma [55]
3 years ago
15

Dora drove 80 km in 40 minutes then 120 km in 1 hour and then the final 200km took him 1 hour 20 minutes. what is his average sp

eed for the whole journey​
Mathematics
1 answer:
bonufazy [111]3 years ago
8 0

9514 1404 393

Answer:

  133 1/3 km/hour

Step-by-step explanation:

Average speed is computed as ...

  average speed = (total distance)/(total time)

  = (80 km +120 km +200 km)/(2/3 + 1 + 1 1/3 hour) = 400 km/(3 hour)

  = 133 1/3 km/hour

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4(x^2 - 5) + 2(3x^2 + 6)
Dmitriy789 [7]

Answer:

=10x2−8

Step-by-step explanation:

4(x2−5)+2(3x2+6)

Distribute:

=(4)(x2)+(4)(−5)+(2)(3x2)+(2)(6)

=4x2+−20+6x2+12

Combine Like Terms:

=4x2+−20+6x2+12

=(4x2+6x2)+(−20+12)

=10x2+−8

5 0
3 years ago
Read 2 more answers
sammy is eleven less than five times Jaime's age. if the sum of their ages is 55, how old is each girl? please help me if i dont
Hoochie [10]

Answer:

Jaime = 11

Sammy = 44

Step-by-step explanation:

It is given that Sammy is eleven less than five times Jaime's age. Use parameter (S) to represent Sammy's age, and parameter (J) to represent Jaime's age. Form an equation based on this given information:

S = 5J - 11

It is given that the sum of the two girl's ages is (55), use an equation to represent this.

S + J = 55

Substitute in the expression for the value of (S) in terms of (J),

(5J - 11) + J = 55

Simplify,

6J - 11 = 55

Inverse operations,

6J - 11 = 55

6J = 66

J = 11

Backsolve for the value of (S), substitute in the value of (J) into the equation for (S) and solve,

S = 5(J) - 11

S = 5(11) -11

S = 55 - 11

S = 44

7 0
3 years ago
Enter the number that belongs in the green box <br><br> PLEASE HELP FAST
ch4aika [34]
The answer in the green box should be 9.
6 0
3 years ago
What is the solution to the inequality? 6x−5&gt;−29 PLEASE HELP THIS IS URGENT!
jolli1 [7]

Answer:

x > - 4

Step-by-step explanation:

Given

6x - 5 > - 29 ( add 5 to both sides )

6x > - 24 ( divide both sides by 6 )

x > - 4

8 0
3 years ago
80. If the value of X and Y in the fraction XZN are both tripled, how does the value of the fraction change? Increases by half?
anygoal [31]

Answer:

Remains the same

Step-by-step explanation:

Given

\frac{XZ}{Y}

Required

What happens when the X and Y are tripled;

Initial\ Fraction = \frac{XZ}{Y}

When both X and Y are tripled, the new fraction is represented below:

New\ Fraction = \frac{3XZ}{3Y}

When the numerator and denominator are divided by their common factor (3), the new fraction becomes

New\ Fraction = \frac{3XZ/3}{3Y/3}

New\ Fraction = \frac{XZ}{Y}

Compare the new fraction with the initial fraction; one would notice that they have the same value;

Hence, the fraction remains the same

6 0
3 years ago
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