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bagirrra123 [75]
4 years ago
5

Help me please with numbers 8-11 thanks

Mathematics
1 answer:
mash [69]4 years ago
4 0
Download photo math rate me a 5 thanks.
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Please help !!
xxMikexx [17]
I hope this helps you

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3 years ago
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How would you find the values of x and y?
Ipatiy [6.2K]
If you havent learnt Sin, Cos yet, let me know, so we can try the other solutions.

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Solve:
riadik2000 [5.3K]

\qquad \qquad\huge \underline{\boxed{\sf Answer}}

Let's solve ~

\qquad \sf  \dashrightarrow \:  \dfrac{2x - 1}{5}  =  \dfrac{x -  2}{2}

\qquad \sf  \dashrightarrow \: 2(2x - 1) = 5(x - 2)

\qquad \sf  \dashrightarrow \: 4x - 2 = 5x - 10

\qquad \sf  \dashrightarrow \: 5x - 4x = -2 + 10

\qquad \sf  \dashrightarrow \: x = 8

Value of x is 8

8 0
2 years ago
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A cell tower is located at and transmits a circular signal that covers three major cities. The three cities are located on the c
Lelu [443]

Answer:

(x+8)^2 +(y-4)^2 = 25

Step-by-step explanation:

Assuming this complete problem: "A cell tower is located at (-8, 4) and transmits a circular signal that covers three major cities. The three cities are located on the circle and have the following coordinates: G (-4, 7), H (-13, 4), and I (-8, -1). Find the equation of the circle"

For this case the generla equation for the circle is given by:

(x-h)^2 +(y-k)^2 = r^2

From the info we know that the tower is located at (-8, 4) so then h = -8 and k = 4, so then we need to find the radius. So we have the equation like this:(x+8)^2 +(y-4)^2 = r^2

If the 3 points are on the circle then satisfy the equation. We can use the first point (-4,7) and if we replace we can find the value for r^2

(-4+8)^2 +(7-4)^2 =25= r^2

So then r = \sqrt{25}=5

And if we replace the second point we got this:

(-13+8)^2 +(4-4)^2 = 25 =r^2

And for the third point we have:

(-8+8)^2 +(-1-4)^2 = 25 =r^2

And we got the same result.

So then our final equation is given:

(x+8)^2 +(y-4)^2 = 25

4 0
4 years ago
The number of significant digits in 650600000 is
kari74 [83]
6506 or 656 is the answer
6 0
3 years ago
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