4.3 ft 3.7 ft 6.5 ft 39.96 ft2 26 it? 19.98 ft? 12.03 ft?

Зх - у = 2 What is the y corddinate

wariber [46]

Answer:

y=3x-2

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

The number of bacteria in a refrigerated food product is given by N ( T ) = 22 T 2 − 123 T + 40 , 6 < T < 36 , where T is

antoniya [11.8K]

Answer:

$N(T(t)) = 1408t^2 - 385.6t - 105.52$

Time for bacteria count reaching 8019: t = 2.543 hours

Step-by-step explanation:

To find the composite function N(T(t)), we just need to use the value of T(t) for each T in the function N(T). So we have that:

$N(T(t)) = 22 * (8t + 1.7)^2 - 123 * (8t + 1.7) + 40$

$N(T(t)) = 22 * (64t^2 + 27.2t + 2.89) - 984t - 209.1 + 40$

$N(T(t)) = 1408t^2 + 598.4t + 63.58 - 984t - 169.1$

$N(T(t)) = 1408t^2 - 385.6t - 105.52$

Now, to find the time when the bacteria count reaches 8019, we just need to use N(T(t)) = 8019 and then find the value of t:

$8019 = 1408t^2 - 385.6t - 105.52$

$1408t^2 - 385.6t - 8124.52 = 0$

Solving this quadratic equation, we have that t = 2.543 hours, so that is the time needed to the bacteria count reaching 8019.

4 0

3 years ago

HELP ASAP Find the 15th term or the geometric sequence 7, -21, 63,

mihalych1998 [28]

<h3>Answer:</h3>

33480783

<h2>Step-by-step explanation:</h2>

Finding the Common Ratio:

We know that the formula for the common ratio of a GP is:

r = aₙ / (aₙ₋₁) (Where n is any integer)

replacing the values, taking n=2

r = -21 / 7

r = -3

Solving for the 15th Term:

We know that the Formula for the nth term of a GP:

G(n) = a * r ⁿ⁻¹ (where a is the first term and r is the common ratio)

replacing the values (taking n = 15 since we need the 15th term)

G(15) = 7 * (-3)¹⁴

G(15) = 33480783

Hence, the 15th term of the given GP is 33480783

5 0

3 years ago

The equation y=2(x-1)^2-5y=2(x−1)

marin [14]

Answer:

(b) It is symmetrical about $x = 1$

Step-by-step explanation:

Given

$y = 2(x - 1)^2 - 5$

See attachment for options

Required

True statement about the graph

First, we check the line of symmetric

$y = 2(x - 1)^2 - 5$

Expand

$y = 2(x^2 - 2x + 1) - 5$

Open bracket

$y = 2x^2 - 4x + 2 - 5$

$y = 2x^2 - 4x -3$

A quadratic equation $y = ax^2 + bx + c$ has the following line of symmetry

$x = -\frac{b}{2a}$

By comparison, the equation becomes:

$x = -\frac{-4}{2*2}$

$x = \frac{4}{4}$

$x = 1$

Hence, the line of symmetry is at: $x = 1$

(b) is true.

8 0

3 years ago

I have no clue how to do any of these problems so if anyone knows any an explanation would be nice.

Sever21 [200]

#1). The length of the whole circumference is (π · D) = 12π .

   120° is 1/3 of 360°, so arc-AB is 1/3 of the whole circumference.

#2). 60° is 1/6 of 360°.
   So arc-CD is 1/6 of the whole circumference (which is given).

#3). The circumference of the circle is (π·D) = 20π .

   70° is (70°/360°) of the whole circle, so arc-XY
   is (70/360) of the whole circumference.

#4). Sorry, I don't remember anything right now about
   angles between chords.
   I hope what I've given you so far is worth 5 points.

7 0

3 years ago