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3 years ago

HELP ASAP PLEASE HELPPP MEEE

Mathematics

2 answers:

Svetlanka [38]3 years ago

5 0

Answer:A= -1.75, B= -0.75, C= -0.25, and D= 0.75

Step-by-step explanation:

dybincka [34]3 years ago

3 0

A=-1.75
b=0.75
c=-0.25
d=0.75

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Consider the first five steps of the derivation of The Quadratic function

Burka [1]

Answer:

Step-by-step explanation:

pick like terms

x² + b²/4a² = -c / a + b²/4a²

b²/4a² = (b/2a)²

x² + (b/2a)² = -c/a + (b/2a)²

(x + b/2a)² = -c/a + (b/2a)² = -c / a + b²/4a² = (-4ac+ b²)/4a²

(x + b/2a)² = (-4ac+ b²)/4a²

square root both sides

√{(x + b/2a)²} = √{(-4ac+ b²)/4a²}

x + b/2a = √(-4ac+ b²) / √(4a²) = √(-4ac+ b²) / 2a = √( b²-4ac) / 2a

x + b/2a = √( b²-4ac) / 2a

subtract b/2a from both sides

x + b/2a -b/2a = {√( b²-4ac) / 2a } -b/2a

x = -b/2a + {√( b²-4ac) / 2a }

the l.c.m is the same

x = {-b±√( b²-4ac)}/2a

7 0

3 years ago

Find the maxium valve C=6x+2y. Subject to the following constraints x≥0, x≤5, y≥0, 4x-y≥1

Vadim26 [7]

Answer:

The maximum value of C is 68

Step-by-step explanation:

we have the following constraints

$x\geq 0$ ----> constraint A

$x\leq 5$ ----> constraint B

$y\geq 0$ ----> constraint C

$4x-y\geq 1$ ----> constraint D

Find out the area of the feasible region, using a graphing tool

The vertices of the feasible region are

(0,0),(5,19),(5,0)

see the attached figure

To find out the maximum value of the objective function C, substitute the value of x and the value of y of each vertex in the objective function and then compare the results

$C=6x+2y$

For (0,0) -----> $C=6(0)+2(0)=0$

For (5,19) -----> $C=6(5)+2(19)=68$

For (5,0) -----> $C=6(5)+2(0)=30$

therefore

The maximum value of C is 68

8 0

3 years ago

Can YOU plz help meh

Aleks [24]

8 × 20= 160; 8 × 4= 32; 160 + 32= 192; 8 × t= 192; 192 ÷ 8= 24; t=24
The answer is t = 24

Hope this helps :)

7 0

3 years ago

Find the missing dimension of the cylinder. Round your answer to the nearest hundredth.

ivann1987 [24]

Answer:

The missing dimension, radius = 6.00 m

Step-by-step explanation:

We are given the following things:

Height of cylinder, $h$ = 15 m

Radius of cylinder, $r = z$ m (Labelled as $z$ )

Volume of cylinder, $V = 1696.5\ m^{3}$

Please refer to the image attached for the dimensions of cylinder as given.

We know that the volume of a cylinder can be given as:

$V = \pi r^{2} h$

Where $r$ is the radius of cylinder

$h$ is the height of cylinder

Putting the values of $V, r \text{ and } h$ :

$1696.5 = \pi z^{2} \times 15\\\Rightarrow z^{2} = 36.01\\\Rightarrow z = 6.00\ m$

Hence, The missing dimension, radius = 6.00 m

6 0

3 years ago

#10. Would I do 3length•1width•2height?

sergeinik [125]

Yes, you are right. the length is 3, the height is 2, and the width is 1

5 0

3 years ago

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