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Luba_88 [7]
3 years ago
8

A magazine editor wants to know what percent of people ski. She chooses people randomly on a winter weekend and calls them at ho

me to ask whether they ski. What is the bias in this situation?
Mathematics
1 answer:
dem82 [27]3 years ago
7 0
The people she's asking are on a winter weekend so they've most likely been skiing. She should've asked random people for a more fair percentage.
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HELP ASAP FOR BRAINLIEST!!
Diano4ka-milaya [45]

Answer:

Not equivalent

Step-by-step explanation:

The three would also be distributed to z making the correct equivalent expression 15+3z

8 0
3 years ago
A number is squared. The result is squared, then that result is squared. The final number is 6561. What was the original number?
MissTica

The original number is 3.

I actually began with the guess-and-check method, but seeing as that won't always work, let's go over the formal way. To get the original number, you first need to determine how many times the number was squared.

To make it simple, let's use x to focus on the exponents. The number was squared 3 times, so x^2, x^2, x^2. Basically, you need to multiply. 2 * 2 * 2 = 8. So, now find the 8th root of 6561 (depending on the calculator, you can just input it). You should come up with 3. Let me know if this part confuses you.

To find the next 2 numbers, you just need to continue the pattern.

6561^2 = 43,046,721

43,046,721^2 = 1,853,020,188,851,841

To my knowledge, which means this could be wrong, they're both perfect squares. Since the number to get them both were whole numbers, they should both have a square root that equals a whole number.

3 0
4 years ago
Which of the following is an extraneous solution of (45-3x)^1/2=x-9?
Iteru [2.4K]

Answer:

C. x =3

Step-by-step explanation:

Extraneous solution is that root of a transformed equation that doesn't satisfy the equation in it's original form because it was excluded from the domain of the original equation.

Let's solve the equation first

\sqrt{45-3x} = x-9\\Taking\ square\ on\ both\ sides\\{(\sqrt{45-3x})}^2 = {(x-9)}^2\\45-3x = x^2-18x+81\\0 = x^2-18x+81-45+3x\\x^2-15x+36 = 0\\x^2-12x-3x+36 = 0\\x(x-12)-3(x-12) = 0\\(x-3)(x-12)\\x-3 = 0\\=> x =3\\x-12 = 0\\x = 12\\We\ will\ check\ the\ solutions\ one\ by\ one\\So,\\for\ x=3\\\sqrt{45-3(3)} = 3-9\\\sqrt{45-9} = -6\\\sqrt{36}= -6\\6\neq -6\\For x=12\\\sqrt{45-3(12)} = 12-9\\\sqrt{45-36} = 6\\\sqrt{36}= 6\\6=6

Hence, we can conclude that x=3 is an extraneous solution of the equation ..

3 0
4 years ago
Divide the given polynomial by the given monomial.​
yanalaym [24]

Answer:

Here are the answers. Need to have 20 characters for answer. Phew

6 0
3 years ago
Please Help me!
snow_lady [41]

Answer:216

Step-by-step explanation:

because 200 times 8 percent = 16 so then you add 16 too 200 and get 216.

6 0
3 years ago
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