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Andru [333]
3 years ago
13

To shift the graph of an equation a certain number of units _____, you need to add that number to the function's equation. A.up

B.down
Mathematics
2 answers:
dolphi86 [110]3 years ago
4 0

Answer:

A. up

Step-by-step explanation:

Adding a value to the y-coordinate of a point shifts the point up by that amount.

kvasek [131]3 years ago
4 0

Answer:

A.up

Step-by-step explanation:

When you have a function and you add a certain number of units to the function you will be shifting the function that same amount of units up, so for example if your function is y=x.

Then when x=1 y=1

If you add 3 units to that function you will have that when X=1 y=4

So you will be shifting the function 3 units up.

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Which is equivalent to RootIndex 3 StartRoot 8 EndRoot Superscript x? RootIndex x StartRoot 8 EndRoot Superscript x 8 Superscrip
dybincka [34]

Answer:

<u>Option 3:</u> 8 Superscript StartFraction x Over 3 EndFraction

Step-by-step explanation:

RootIndex 3 StartRoot 8 EndRoot Superscript x

  • ∛8ˣ = 8^{x/3}

<u>Options</u>:

RootIndex x StartRoot 8 EndRoot Superscript x

  • (\sqrt[x]{8})^x    incorrect

8 Superscript StartFraction 3 Over x EndFraction

  • 8^{3/x}    incorrect

8 Superscript StartFraction x Over 3 EndFraction

  • 8^{x/3}       correct

8 Superscript 3 x

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7 0
3 years ago
Simplify.<br><br> −9x − 3 − (5x + 3) − 7
Ket [755]

Answer: I got -14x-13

But it sounds wrong but I have a picture

Step-by-step explanation:

4 0
4 years ago
The areaot a square is 36 cm? What<br> is the side length, s?
vichka [17]

Answer: 6

Step-by-step explanation: To find the side length of a square, you need to find the square root of the area because the side length squared is the area.

5 0
3 years ago
If g(x)=4x-6 then g^-1(x)=?<br> (1) -4x+6<br> (2)-1/4x+1/6<br> (3)1/4x+3/2<br> (4)1/4x+6
kati45 [8]

Given:

g(x)=4x-6

To find:

The function g^{-1}(x).

Solution:

we have,

g(x)=4x-6

Put g(x)=y.

y=4x-6

Interchange x and y.

x=4y-6

Isolate y.

x+6=4y

\dfrac{x+6}{4}=y

y=\dfrac{x+6}{4}

Substitute y=g^{-1}(x).

g^{-1}(x)=\dfrac{x+6}{4}

g^{-1}(x)=\dfrac{x}{4}+\dfrac{6}{4}

g^{-1}(x)=\dfrac{x}{4}+\dfrac{3}{2}

Therefore, the correct option is (3).

4 0
3 years ago
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