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3 years ago

3/4 Divided by 3/4 equals what

Mathematics

2 answers:

AlekseyPX3 years ago

8 0

3/4 divided by 3/4 is one

luda_lava [24]3 years ago

5 0

Answer:

It is 1

Step-by-step explanation:

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A student finds the sum of the angle measures in an octagon by multiplying 7 • 180°. What is the student's error?

Lostsunrise [7]

The student should compute 6*180 = 1080 because of the formula

S = 180(n-2)

We have n = 8 sides which leads the n-2 part to become n-2 = 8-2 = 6

7 0

3 years ago

What is the value of x when y equals 2 in the equation y equals x over 4 - 7

Alex

The value of x when y = 2 is x = 36

Step-by-step explanation:

The equation that we have in this problem is:

$y=\frac{x}{4}-7$

In order to find the value of x when y is equal to

y = 2

We need to re-arrange the equation making x the subject.

We proceed as follows:

1) We add +7 on both sides:

$y+7=\frac{x}{4}-7+7\\y+7=\frac{x}{4}$

2) Now we multiply both sides by 4:

$4(y+7)=\frac{x}{4}\cdot 4\\x=4(y+7)$

3) Now we can substitute y = 2 and find the value of x:

$x=4(2+7)=4(9)=36$

Learn more about equations:

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#LearnwithBrainly

5 0

3 years ago

Points M, N, and P are respectively the midpoints of sides AC , BC , and AB of △ABC. Prove that the area of △MNP is on fourth of

Hunter-Best [27]

Answer:

The area of △MNP is one fourth of the area of △ABC.

Step-by-step explanation:

It is given that the points M, N, and P are the midpoints of sides AC, BC and AB respectively. It means AC, BC and AB are median of the triangle ABC.

Median divides the area of a triangle in two equal parts.

Since the points M, N, and P are the midpoints of sides AC, BC and AB respectively, therefore MN, NP and MP are midsegments of the triangle.

Midsegments are the line segment which are connecting the midpoints of tro sides and parallel to third side. According to midpoint theorem the length of midsegment is half of length of third side.

Since MN, NP and MP are midsegments of the triangle, therefore the length of these sides are half of AB, AC and BC respectively. In triangle ABC and MNP corresponding side are proportional.

$\triangle ABC \sim \triangle NMP$

$MP\parallel BC$

$MP=\frac{BC}{2}$

By the property of similar triangles,

$\frac{\text{Area of }\triangle MNP}{\text{Area of }\triangle ABC}=\frac{PM^2}{BC^2}$

$\frac{\text{Area of }\triangle MNP}{\text{Area of }\triangle ABC}=\frac{(\frac{BC}{2})^2}{BC^2}$

$\frac{\text{Area of }\triangle MNP}{\text{Area of }\triangle ABC}=\frac{1}{4}$

Hence proved.

5 0

3 years ago

The ordered pair (a,b) satisfies the inequality y < x + 6. which statement is true ?

natka813 [3]

Answer:

True: If you add 6 to a, this will be greater than b.

Step-by-step explanation:

If the ordered pair (a,b) satisfies the inequality y < x + 6, then the coordinates of this point satisfy the inequality. Substitute into the inequality x = a and y =b:

$b$