Answer:
ok
Step-by-step explanation:
ok
Answer:
8
Step-by-step explanation:
(10-4)+20/20
6+20/10
6+2
8
9x-8=9x-3/2 X3
9x-8=27x-9/2
2(9x-2)=27x-9
18x-4 =27x-9
18x-27x=-9+4
-9x =-5
9x=5
X=5/9 answer
Answer:
(-3, 4)
Step-by-step explanation:
let the point P(x, y)
x = (5/7 × (-1+8)) + (-8)
= (5/7 × 7) -8 = 5-8 = -3
y = (5/7 × (8+6)) + (-6)
= (5/7 × 14) -6 = 10-6 = 4
so, P => (-3 , 4)
= 1/2kx2
U = potential energy of a spring at a certain position
k = the spring constant, specific to the spring, with units N/m.
x = distance the spring is stretched or compressed away from equilibrium
Potential Energy: Elastic Formula Questions:
1) A spring, which has a spring constant k = 7.50 N/m, has been stretched 0.40 m from its equilibrium position. What is the potential energy now stored in the spring?
Answer: The spring has been stretched x = 0.40 m from equilibrium. The potential energy can be found using the formula:
U = 1/2kx2
U = 1/2(7.50 N/m)(0.40 m)2
U = 0.60 N∙m
U = 0.60 J
