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Ierofanga [76]
3 years ago
10

Which number is equivalent to 0.15 x 10³?

Mathematics
2 answers:
Doss [256]3 years ago
5 0
0.15 x 100 (10³) = 150...
DanielleElmas [232]3 years ago
4 0
It equals 150.......
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PLEASE HELP!!! I need an urgent answer and I'll give brainiest just please answer this easy question!
Leya [2.2K]

Answer:

y , add 7, multiply by 3, then subtract 6.or Solve the system of equations and choose the correct answer from the list of options. x − y = 7 y = 3x + 12 2 over 19 comma 2 over 33 negative 2 over 19 comma negative 33 over 2 negative 19 over 2 comma negative 33 over 2 19 over 2 comma 33 over 2

Step-by-step explanation:

3 0
3 years ago
Find the value of w in the triangle.<br> x<br> 1359<br> 770
Alborosie

Answer:

Multiply each le and divde from the one on the left

Step-by-step explanation:

4 0
3 years ago
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What is x? <br><br> 7x + 9= 5x-3
Pani-rosa [81]

Answer:

-6

Step-by-step explanation:

7x + 9 = 5x -3

-5x -5x

2x+9=-3

-9 -9

2x=-12

divide by 2

x = -6

3 0
3 years ago
Consider a particle moving along the x-axis where x(t) is the position of the particle at time t, x' (t) is its velocity, and x'
vodka [1.7K]

Answer:

a) v(t) =x'(t) = \frac{dx}{dt} = 3t^2 -12t +9

a(t) = x''(t) = v'(t) =6t-12

b)  0

c) a(t) = x''(t) = v'(t) =6t-12

When the acceleration is 0 we have:

6t-12=0, t =2

And if we replace t=2 in the velocity function we got:

v(t) = 3(2)^2 -12(2) +9=-3

Step-by-step explanation:

For this case we have defined the following function for the position of the particle:

x(t) = t^3 -6t^2 +9t -5 , 0\leq t\leq 10

Part a

From definition we know that the velocity is the first derivate of the position respect to time and the accelerations is the second derivate of the position respect the time so we have this:

v(t) =x'(t) = \frac{dx}{dt} = 3t^2 -12t +9

a(t) = x''(t) = v'(t) =6t-12

Part b

For this case we need to analyze the velocity function and where is increasing. The velocity function is given by:

v(t) = 3t^2 -12t +9

We can factorize this function as v(t)= 3 (t^2- 4t +3)=3(t-3)(t-1)

So from this we can see that we have two values where the function is equal to 0, t=3 and t=1, since our original interval is 0\leq t\leq 10 we need to analyze the following intervals:

0< t

For this case if we select two values let's say 0.25 and 0.5 we see that

v(0.25) =6.1875, v(0.5)=3.75

And we see that for a=0.5 >0.25=b we have that f(b)>f(a) so then the function is decreasing on this case.  

1

We have a minimum at t=2 since at this value w ehave the vertex of the parabola :

v_x =-\frac{b}{2a}= -\frac{-12}{2*3}= -2

And at t=-2 v(2) = -3 that represent the minimum for this function, we see that if we select two values let's say 1.5 and 1.75

v(1.75) =-2.8125< -2.25= v(1.5) so then the function sis decreasing on the interval 1<t<2

2

We see that the function would be increasing.

3

For this interval we will see that for any two points a,b with a>b we have f(a)>f(b) for example let's say a=3 and b =4

f(a=3) =0 , f(b=4) =9 , f(b)>f(a)

The particle is moving to the right then the velocity is positive so then the answer for this case is: 0

Part c

a(t) = x''(t) = v'(t) =6t-12

When the acceleration is 0 we have:

6t-12=0, t =2

And if we replace t=2 in the velocity function we got:

v(t) = 3(2)^2 -12(2) +9=-3

5 0
4 years ago
+ PRINCIPLES OF MATHEMATICS
GREYUIT [131]

Answer:

$9,840

Step-by-step explanation:

Let the money earned from college be 'x'.

Given:

Total money earned from the two jobs = $50,450

Money earned at the store = 1250 + 4(Money earned at college)

∴ Money earned at the store = 1250 +4x

Now, total money earned by Erica is the sum of money earned at store and college. Therefore,

Total money = Money at store + Money at college

50450=1250+4x+x\\5x+1250=50450\\5x=50450-1250\\5x=49200\\x=\frac{49200}{5}=\$9840

Therefore, the money earned by Erica from her job at the college is $9,840.

3 0
3 years ago
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