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ludmilkaskok [199]

3 years ago

14

The kinked demand curve model assumes that if a firm raises its price, then its rivals will _____ the price increase, but if a f

irm lowers its price, its rivals will _____ the price decrease.

1 answer:

Anni [7]3 years ago

7 0

Answer:

idk

Step-by-step explanation:

idk

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HEEEEEELLLLLLLLPPPPPPPP! Plz

ELEN [110]

Answer:

non linear

Step-by-step explanation:

4 0

3 years ago

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I'm having trouble with #2. I've got it down to the part where it would be the integral of 5cos^3(pheta)/sin(pheta). I'm not sur

Butoxors [25]

$\displaystyle\int\frac{\sqrt{25-x^2}}x\,\mathrm dx$

Setting $x=5\sin\theta$ , you have $\mathrm dx=5\cos\theta\,\mathrm d\theta$ . Then the integral becomes

$\displaystyle\int\frac{\sqrt{25-(5\sin\theta)^2}}{5\sin\theta}5\cos\theta\,\mathrm d\theta$
$\displaystyle\int\sqrt{25-25\sin^2\theta}\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta$
$\displaystyle5\int\sqrt{1-\sin^2\theta}\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta$
$\displaystyle5\int\sqrt{\cos^2\theta}\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta$

Now, $\sqrt{x^2}=|x|$ in general. But since we want our substitution $x=5\sin\theta$ to be invertible, we are tacitly assuming that we're working over a restricted domain. In particular, this means $\theta=\sin^{-1}\dfrac x5$ , which implies that $\left|\dfrac x5\right|\le1$ , or equivalently that $|\theta|\le\dfrac\pi2$ . Over this domain, $\cos\theta\ge0$ , so $\sqrt{\cos^2\theta}=|\cos\theta|=\cos\theta$ .

Long story short, this allows us to go from

$\displaystyle5\int\sqrt{\cos^2\theta}\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta$

to

$\displaystyle5\int\cos\theta\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta$
$\displaystyle5\int\dfrac{\cos^2\theta}{\sin\theta}\,\mathrm d\theta$

Computing the remaining integral isn't difficult. Expand the numerator with the Pythagorean identity to get

$\dfrac{\cos^2\theta}{\sin\theta}=\dfrac{1-\sin^2\theta}{\sin\theta}=\csc\theta-\sin\theta$

Then integrate term-by-term to get

$\displaystyle5\left(\int\csc\theta\,\mathrm d\theta-\int\sin\theta\,\mathrm d\theta\right)$
$=-5\ln|\csc\theta+\cot\theta|+\cos\theta+C$

Now undo the substitution to get the antiderivative back in terms of $x$ .

$=-5\ln\left|\csc\left(\sin^{-1}\dfrac x5\right)+\cot\left(\sin^{-1}\dfrac x5\right)\right|+\cos\left(\sin^{-1}\dfrac x5\right)+C$

and using basic trigonometric properties (e.g. Pythagorean theorem) this reduces to

$=-5\ln\left|\dfrac{5+\sqrt{25-x^2}}x\right|+\sqrt{25-x^2}+C$

4 0

3 years ago

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What is the height, h, of one of the triangles?<br> 4 ft<br> 8 ft<br> 7 ft<br> 14 ft

vagabundo [1.1K]

Answer:

4 ft

Step-by-step explanation:

the width of two triangles is given as 8 just divide by 2 since answer is asking for only one triangle

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Pleas hell will mark brainliest

OverLord2011 [107]

Answer:

The answer is b.

Step-by-step explanation:

Eduardo sold 1 white chocolate chip and 3 oatmeal.

15 + (18 x 3) = 69

Heidi sold 2 white chocolate chip and 1 oatmeal.

(15 x 2) + 18 = 48

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3 years ago

How is shape D diffrent from shapes A,B,C

Allushta [10]

Answer: D

Step-by-step explanation: Only has 2 acute angles and 2 obtuse angles

Let me know if I'm wrong. If not I'm glad I could help

5 0

2 years ago