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3 years ago

Yesterday, Jack drove 33 and one half

Mathematics

2 answers:

tangare [24]3 years ago

5 0

Answer:

His car runs 26.8 miles per gallon.

Step-by-step explanation:

Divide to get the unit rate:

33.5 mi

------------- = 26.8 mpg

1.25 gal

borishaifa [10]3 years ago

3 0

change each mixed number to an improper fraction

33 1/2 = (2*33 +1)/2 67/2

1 1/4 = (4*1+1)/4 = 5/4

67/2 divided by 5/4

copy dot flip

67/2 * 4/5

268/10

26 8/10

26 4/5 miles per gallon

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3 years ago

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Answer:

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2 years ago

Find the domain.<br> p(x) = x^2+ 2

MrRissso [65]

Answer:

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

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3 years ago

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chubhunter [2.5K]

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3 years ago

35 solve the following syste

blondinia [14]

Part A: The solution is $(-0.923,5.692)$

Part B: The point $(3,7)$ is not in the solution set.

Explanation:

Part A: The given inequalities are $3 x+4 y>20$ and $x$

The solution can be determined by solving the two inequalities by substitution method.

Changing inequalities to equality, we have,

$x=3 y-18$ and $3 x+4 y=20$

Let us substitute $x=3 y-18$ in the equation $3 x+4 y=20$ , we get,

$3 (3y-18)+4 y=20$

$9y-54+4y=20$

$13y=74$

$y=5.692$

Substituting $y=5.692$ in $x=3 y-18$ , we get,

$x=3 (5.692)-18$

$=17.076-18$

$x=-0.923$

Thus, the solution set is $(-0.923,5.692)$

Part B: Now, we shall determine whether the point $(3,7)$ is in the solution set.

Let us substitute the point $(3,7)$ in the inequalities $3 x+4 y>20$ and $x$ , we get,

$3 (3)+4 (7)>20$

$9+28>20$

$37>20$

Also, substituting $(3,7)$ in $x$ , we get,

$3$

Since, the point $(3,7)$ does not satisfy one of the inequality $x$ , the solution set does not contain the point $(3,7)$

Thus, the point $(3,7)$ is not in the solution set.

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2 years ago

​Yesterday, Jack drove 33 and one half

Yesterday, Jack drove 33 and one half