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kondor19780726 [428]
3 years ago
14

The function Q(x)=2x^2-kx+18. For what value of k does Q(x) have one distinct real solution? (NEEDS TO BE DONE WITHIN 2 HOURS!)

Mathematics
1 answer:
Aliun [14]3 years ago
4 0

Answer:

k = 12

Step-by-step explanation:

Given:

The equation Q(x)=2x^2-kx+18

To find:

Value of k = ? for which the given equation has one distinct real solution.

Solution:

The given equation is a quadratic equation.

There are always two solutions of a quadratic equation.

For the equation: ax^{2} +bx+c=0 to have one distinct solution:

b^2 - 4ac = 0

Here,

a = 2,

b = -k and

c = 18

Putting the values, we get:

(-k)^2 - 4\times 2\times 18 = 0\\\Rightarrow k^2 = 18\times 8\\\Rightarrow k^2 =144\\\Rightarrow k = 12

The equation becomes:

Q(x)=2x^2-12x+18

And the one root is:

2(x^2-6x+9 ) = 0\\\Rightarrow 2(x-3)^2=0\\\Rightarrow x = 3

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For the given function, x can have what value?
Lyrx [107]

Answer:

x cannot be -4,-3, or 13

x can be anything else

Step-by-step explanation:

There are infinitely many values x can take where the relation above will be a function.

For it to be a function, you just need to make sure each x is only assigned one y value.

So x couldn't be -4 because it would by assigned to y=2 and y=0.

x couldn't be -3 because it would be assigned to y=1 and y=0.

x couldn't be 13 because it would be assigned to y=5 and y=0.

So as long as x is not chosen to be -4,-3, or 13 your relation here is a function.

5 0
3 years ago
Priya's family exchanged 250 dollars for 4,250 pesos. Priya bout a sweater fo 510 pesos. How many dollars did the sweater cost?
Elena L [17]
30 dollars.

1 dollar = 17 pesos.

510 ÷ 17 =30
4 0
3 years ago
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Add the two expressions. 8.9x−5 and −6.8x+8
Cloud [144]
The answer is 2.1x+3 
6 0
3 years ago
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The value of sqroot -4 is not -2 because
masha68 [24]
I’m pretty sure the answer is b! hope this helps!!
4 0
3 years ago
Write and solve a system of equations to determine how many tickets were sold before and at the music festival. PLEASE HELPPP
strojnjashka [21]

b = number of tickets sold before

a = number of tickets sold after

cost of a ticket = number of tickets times cost per ticket

before cost = 39.95b

after cost = 54.95a

total cost = 925000

39.95b + 54.95a = 925000

total number tickets = 20000

b + a = 20000

we have

39.95b + 54.95a = 925000

b + a = 20000

multiply second equation by -39.95 and add to first equation

39.95b + 54.95a = 925000

-39.95b-39.95a = -799000 +

0b+15a = 126000

15a = 126000

divide bot sides by 15

a = 8400

sub back

b + a = 20000

b+8400 = 20000

minus 8400 both sides

b = 11600

11,600 tickets sold before

8400 tickets sold after

3 0
3 years ago
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