We have 20 chances out of 100 which is 20/100=1/5 other known as 1 in 5 chance
The even numbers are 2, 4, 6, .., 100. 50 chances out of 100 which is 50/100=1/2 other know as 1 in 2 chance
I think it could be 13,17, and 15.
If I am wrong then I am sorry
4d=56
d=14. Ad a result, Dorothy is 14 years old. Hope it help!
Answer:
The point estimate for this problem is 0.48.
Step-by-step explanation:
We are given that a University wanted to find out the percentage of students who felt comfortable reporting cheating by their fellow students.
A survey of 2,800 students was conducted and the students were asked if they felt comfortable reporting cheating by their fellow students. The results were 1,344 answered "Yes" and 1,456 answered "no".
<em>Let </em>
<em> = proportion of students who felt comfortable reporting cheating by their fellow students</em>
<u></u>
<u>Now, point estimate (</u>
<u>) is calculated as;</u>
where, X = number of students who answered yes = 1,344
n = number of students surveyed = 2,800
So, Point estimate (
) =
= <u>0.48 or 48%</u>
The answer should be A. For example, if x = 1, and the ratio between x and y is y is 5 times greater than x, then y would equal 5, which is only true in A.
Or, use the number 5 as an example. If x = 5, and the ratio between x and y is y is 5 times greater than x, then y is 5.
And if you put that into A, y = 5x, it becomes 25 = 5(5)
Then 25 = 25, which is true!