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Lyrx [107]
3 years ago
8

Please help me with this question

Mathematics
1 answer:
Doss [256]3 years ago
7 0

Answer: 275 cm

volume = length x width x height

v = 6.25 x 8 x 5.5

v = 275

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|2k+3|=7<br>absolute value
faust18 [17]

Answer:

2

Step-by-step explanation:

2k+3=7

2k=4

k=2

5 0
3 years ago
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Please help me with this please
eimsori [14]

<u>Part</u><u> </u><u>(</u><u>a</u><u>)</u>

Using the quotient rule, the blank is 11/5.

<u>Part</u><u> </u><u>(</u><u>b</u><u>)</u>

Using the product rule, the blank is 9.

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6 0
2 years ago
A square field has an area of 479 ft what is the approximate length of a size of the field
MissTica

Answer:

21.9 ft

Step-by-step explanation:

The area of a square is the square of the side length, so the side length is the square root of the area:

... s = √(479 ft²) ≈ 21.886 ft

This is approximately 21.9 ft.

4 0
3 years ago
mr. Hill measures the screws on his workbench he records the measurements in the chart mr. Hale found another screw using inch r
victus00 [196]

3 1/2

Hopes that helps

3 0
3 years ago
A 2.2 kg ball strikes a wall with a velocity of 7.4 m/s to the left. The ball bounces off with a velocity of 6.2 m/s to the righ
Naya [18.7K]

Answer:

The constant force exerted on the ball by the wall is 119.68 N.

Step-by-step explanation:

Consider the provided information.

It is given that the mass of the ball is m = 2.2 kg

The initial velocity of the ball towards left is 7.4 m/s

So the momentum of the ball when it strikes is = 2.2\times 7.4=16.28

The final velocity of the ball is -6.2 m/s

So the momentum of the ball when it strikes back is = 2.2\times -6.2=-13.64

Thus change in moment is: 16.28-(-13.64)=29.92

The duration of force exerted on the ball t = 0.25 s

Therefore, the constant force exerted on the ball by the wall is:

\frac{29.92}{0.25}=119.68

Hence, the constant force exerted on the ball by the wall is 119.68 N.

6 0
3 years ago
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