AB = 6 cm, AC = 12 cm, CD = ?
In triangle ABC, ∠CBA = 90°, therefore in triangle BCD ∠CBD = 90° also.
Since ∠BDC = 55°, ∠CBD = 90°, and there are 180 degrees in a triangle, we know ∠DCB = 180 - 55 - 90 = 35°
In order to find ∠BCA, use the law of sines:
sin(∠BCA)/BA = sin(∠CBA)/CA
sin(∠BCA)/6 cm = sin(90)/12 cm
sin(∠BCA) = 6*(1)/12 = 0.5
∠BCA = arcsin(0.5) = 30° or 150°
We know the sum of all angles in a triangle must be 180°, so we choose the value 30° for ∠BCA
Now add ∠BCA (30°) to ∠DCB = 35° to find ∠DCA.
∠DCA = 30 + 35 = 65°
Since triangle DCA has 180°, we know ∠CAD = 180 - ∠DCA - ∠ADC = 180 - 65 - 55 = 60°
In triangle DCA we now have all three angles and one side, so we can use the law of sines to find the length of DC.
12cm/sin(∠ADC) = DC/sin(∠DCA)
12cm/sin(55°) = DC/sin(60°)
DC = 12cm*sin(60°)/sin(55°)
DC = 12.686 cm
Answer:
The answer is 2.89 in 2dp
3 cube is 27
27 minus 6.8 is 20. 2
20. 2 decide by 7 is 2.89
To solve this you need to divided 0.33 in 2. Because 2 meters. So, 0.165 per minute. But the question is per second, so we need to divided 0.165 by 60. In doing that, you get 0.00275 meters per second. For the 2nd question, we do 0.165 multiplied by 3 to get the answer of 0.495 meters in 3 minutes. I hope my answer helps!
1. 2 X 3/8 X 3 X 3/7
Reduce the numbers with 2
2. 3/4 X 3 X 3/7
Multiply the fractions
To get 9/28 then x by 3
Answer should be 27/28
The polynomial function is P(x) = x^3(x + 1)^3(x -1)
<h3>How to determine the polynomial function?</h3>
The zeros of the polynomial and the multiplicities are given as:
- -1 as a zero of multiplicity 3,
- 0 as a zero of multiplicity 3,
- 1 as a zero of multiplicity 1
The degree is given as
Degree = 7
The polynomial is represented as:
P(x) = (x - zero)^multiplicity
Using the above format, we have
P(x) = (x + 1)^3(x - 0)^3(x -1)
This gives
P(x) = x^3(x + 1)^3(x -1)
Hence, the polynomial function is P(x) = x^3(x + 1)^3(x -1)
Read more about polynomial function at
brainly.com/question/2833285
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