Question

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Answer 1

Answer:

Step-by-step explanation:

$\frac{cot \theta}{cosec \theta + 1} = \frac{cosec\theta -1} {cot \theta}$

$L H S$

       $\frac{cot \theta }{cosec \theta + 1 } \times \frac{cosec \theta - 1}{cosec \theta -1}$             $[ \ multiplying \ and \ dividng \ by \ (cosec \theta - 1) \ ]$

     $= \frac{cot \theta \times (cosec \theta - 1)}{(cosec ^2\theta -1)}$                   $[ \ (a -b)(a+b) = a^2 - b^2 \ ]$

     $= \frac{cot \theta \times (cosec \theta - 1)}{cot^2 \theta}$                   $[ \ cosec^2\theta - 1 = cot^2 \theta \ ]$

     $= \frac{cosec \theta - 1 }{cot \theta} \\\\= RHS$

   

                           

Answer 2

Answer:

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