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meriva
2 years ago
13

Please help guys I will be helping u in the days to come n follow u for sure​

Mathematics
2 answers:
Leya [2.2K]2 years ago
4 0

Answer:

Step-by-step explanation:

\frac{cot \theta}{cosec \theta + 1} = \frac{cosec\theta -1} {cot \theta}

L H S

       \frac{cot \theta }{cosec \theta + 1 } \times \frac{cosec \theta - 1}{cosec \theta -1}             [  \ multiplying \ and \  dividng \ by  \ (cosec \theta - 1) \ ]

     =  \frac{cot \theta \times (cosec \theta - 1)}{(cosec ^2\theta -1)}                   [ \ (a -b)(a+b) = a^2 - b^2 \ ]

     =  \frac{cot \theta \times (cosec \theta - 1)}{cot^2 \theta}\\ \\                   [ \ cosec^2\theta  - 1 = cot^2 \theta \ ]

     = \frac{cosec \theta - 1 }{cot \theta} \\\\= RHS

   

                           

love history [14]2 years ago
3 0

Answer:

I'd 7587163850

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