Answer:
3
3
5
2
Step-by-step explanation:
What kind of math is this and what grade are you in?
Answer: Choice C
x/w and z/(y+v)
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Explanation:
All answer choices have that first fraction with a denominator of w. This implies that AB = w is the hypotenuse. This only applies to triangle ABD.
Focus on triangle ABD. It has an opposite leg of AD = x, when the reference angle is ABD (or angle B for short).
So we can say sin(ABD) = opposite/hypotenuse = AD/AB = x/w
x/w is one of the answers
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Also note how y+v is the same for each denominator in the second fraction. y+v is the hypotenuse of triangle ABC. When the reference angle is ABD (aka angle ABC), the opposite side of this same triangle is AX = z
Therefore,
sin(ABD) = sin(ABC) = opp/hyp = AC/BC = z/(y+v)
z/(y+v) is the other answer
Side note: triangle ACD is not used at all.
The answer to 2 is 14 and the answer to 4 is b
We have two points so we can find the gradient using y1-y2/x1-x2
gradient = 21-27/2-8
= 1
we know the form for any linear equation is y = mx + c
we have m and a point so we can substitute in point (2,21) to find c
21 = 1 x 2 + c
c = 19
therefore, the equation is y = x + 19
Answer:
6.28571428571
Step-by-step explanation:
