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azamat
3 years ago
6

Please help me solve for W

Mathematics
2 answers:
mariarad [96]3 years ago
8 0
W+1/9 = 5
 W = 5-1/9
 = [(5*9)-1]/9
= [45-1]/9
= 44/9
OLga [1]3 years ago
7 0
w+\frac{1}{9}=5\\
w=5-\frac{1}{9}\\w=\frac{45}{9}-\frac{1}{9}\\
w=\frac{44}{9}

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Juli2301 [7.4K]
The answer for this question is A
8 0
4 years ago
Need help pls<br>thank you in advance ​
ira [324]

Answer:

<h3><u>Mean</u></h3>

<u />

\textsf{Mean}\:\overline{X}=\sf \dfrac{\textsf{sum of all the data values}}{\textsf{total number of data values}}

\implies \sf Mean\:(Nilo)=\dfrac{5+6+14+15}{4}=\dfrac{40}{4}=10

\implies \sf Mean\:(Lisa)=\dfrac{8+9+11+12}{4}=\dfrac{40}{4}=10

<h3><u>Standard Deviation</u></h3>

\displaystyle \textsf{Standard Deviation }s=\sqrt{\dfrac{\sum X^2-\dfrac{(\sum X)^2}{n}}{n-1}}

\begin{aligned}\displaystyle \textsf{Standard Deviation (Nilo)} & =\sqrt{\dfrac{(5^2+6^2+14^2+15^2)-\dfrac{(5+6+14+15)^2}{4}}{4-1}}\\\\& = \sqrt{\dfrac{482-\dfrac{40^2}{4}}{3}}\\\\& = \sqrt{\dfrac{82}{3}}\\\\& = 5.23\end{aligned}

\begin{aligned}\displaystyle \textsf{Standard Deviation (Lisa)} & =\sqrt{\dfrac{(8^2+9^2+11^2+12^2)-\dfrac{(8+9+11+12)^2}{4}}{4-1}}\\\\& = \sqrt{\dfrac{410-\dfrac{40^2}{4}}{3}}\\\\& = \sqrt{\dfrac{10}{3}}\\\\& = 1.83\end{aligned}

<h3><u>Summary</u></h3>

Nilo has a mean score of 10 and a standard deviation of 5.23.

Lisa has a mean score of 10 and a standard deviation of 1.83.

The <u>mean</u> scores are the <u>same</u>.

Nilo's standard deviation is higher than Lisa's.  Therefore, Nilo's test scores are more <u>spread out</u> that Lisa's, which means Lisa's test scores are more <u>consistent</u>.

5 0
2 years ago
The probability that a car will have a flat tire while driving through a certain tunnel is 0.00005. Use the Poisson distribution
timama [110]

Answer: D. 0.1217

Step-by-step explanation:

Given : The probability that a car will have a flat tire while driving through a certain tunnel :p=0.00005.

n= 14000

Then, the mean number of cars will have a flat tire while driving through a certain tunnel = np

=14000\times0.00005=0.7

Poisson Distribution Formula : P(x)=\dfrac{e^{-\lambda} \lambda^x}{x!}

For x= 2

P(2)=\dfrac{e^{-0.7} (0.7)^2}{2!}=0.121663399429\approx0.1217

Hence, the required probability = 0.1217

5 0
4 years ago
Could u help me with this I got stuck and I don’t know how to finish
NikAS [45]

Answer:

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Step-by-step explanation:

The IQR is the width of the box of the box plot. The box runs from 20 to 30, so its width is 10.

5 0
3 years ago
Read 2 more answers
Natalia bought 4 boxes of pencils and 9 reams of paper for 75$. Ronnie by eight boxes of pencils and five reams of paper for 67.
storchak [24]

Answer:a box of pencil cost=$4.395

And a ream of paper cost=$6.38

Step-by-step explanation:

Let the cost of box of pencil be represented as p

And the cost of ream of paper be represented as r

Such that

4 boxes of pencils and 9 reams of paper costing 75$ be represented as

4p+9r=75-----equation 1

Also, eight boxes of pencils and five reams of paper for 67 be represented as

8p + 5r=67------equation 2

Solving

4p+9r=75-----equation 1

8p + 5r=67------equation 2

By elimination method, multiply equation 1 by 2 and equation 2 by 1

8p +18r=150---equation 3

8p+5r=67----equation 4

Subtracting equation 4 from equation 3

13r=83

r=83/13

r=6.38

Putting the value of r=6.38 in equation 1 to solve for p, we have

4p+9r=75

4p+9(6.38)=75

4p+57.42= 75

4p=75-57.42

4p=17.58

p=17.58/4

p=4.395.

Therefore a box of pencil cost=$4.395

And a ream of paper cost=$6.38

8 0
3 years ago
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