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3 years ago

9

Round each number to the nearest tenth.

1 answer:

NNADVOKAT [17]3 years ago

8 0

Hello!

To find this, we need to solve the solution.

376.64 - 109.38 = 267.

267.26 rounded to the nearest tenth is 267.3

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John has finished compiling a list of the various members of the joint application development (JAD) group and the list is as fo

dolphi86 [110]

Answer:

d. His own

Step-by-step explanation:

John is the leader of the particular project team. He is in charge of delegating different tasks to his team members and also endure that everything is in order. He will also develop the necessary agenda and formulate the final report of the project. Therefore, the name that will be attached on the final tasks is his own.

8 0

3 years ago

What is the Slope and Y-intercept?

Ilya [14]

Step-by-step explanation:

<u>Slope formula:</u> $\frac{y2}{x2} -\frac{y1}{x1} =m$

m = slope

Take 2 points from the table.

(-3, 5) and (-2, 2).

<u>Add these points to the formula:</u>

$\frac{2}{-2} -\frac{5}{-3} =$

<u>Solve:</u>

<u /> $\frac{2}{-2} -\frac{5}{-3} =\frac{-3}{1}$

Option 1 is correct.

Y-intercept is where <u>x = 0.</u>

On the table, it's showing at x = 0, <u>y = -4.</u>

The y-intercept equals -4.

6 0

3 years ago

Read 2 more answers

What is the vertex of the function x2 - 6x + 8 = 0?

RUDIKE [14]

<u>Answer: </u>

The vertex of the function $\bold{x^{2} -6 x + 8 = 0}$ is (h,k) = (3 , -1)

<u>Solution: </u>

The vertex form of quadratic equation is generally given as,

$f(x) = a(x - h)^{2} + k$

Where h,k is the vertex of the parabola.

From question, given that $x^{2}-6 x+8=0$ .

we have to find the vertex of the function.

Let us first convert the given quadratic equation to vertex form (eqn 1)

$x^{2}-6 x+8=0$

$x^{2}-6 x=-8$

By adding “9” on both sides of equation, we get

$x^{2}-6 x+9=-8+9$

$x^{2}-6 x+9=1$

By using the identity $(a-b)^{2}=a^{2}-2 a b+b^{2}$ ,the right hand side of above equation becomes,

$(x-3)^{2}=1$

$(x-3)^{2}-1=0$

Now,the equation $(x-3)^{2}-1=0$ is of the vertex form.

By comparing $(x-3)^{2}-1=0$ with $a(x-h)^{2}+k$

we get the values of (h,k)

a = 1; h = 3; k = -1

hence the vertex of the function $x^{2}-6 x+8=0$ is (h,k) = (3 , -1)

5 0

3 years ago

How do we do this please help thank u

murzikaleks [220]

Answer:

95%.

Step-by-step explanation:

That would be (3.42 * 100) / 3.60

= 95% (95 percent).

Percent means ' per hundred'.

8 0

3 years ago

Read 2 more answers

Given the function<br> Calculate the following values:<br> f( - 1) =<br> f(0)<br> f(2)=

Alecsey [184]

-1 is less than 0, so you use the first equation:

3(-1) +2 = -3+2 = -1

f(-1) = -1

For 0 use the 2nd equation:

3(0) + 4 = 0+4 = 4

f(0) = 4

For 2 use the 2nd equation:

3(2) + 4 = 6+4 = 10

f(2) = 10

6 0

3 years ago