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podryga [215]
3 years ago
6

What's 7⁄8 as a decimal? A. 8.7 B. .875 C. .78 D. 7.8

Mathematics
2 answers:
LuckyWell [14K]3 years ago
3 0
7/8 is equal to 0.875
miss Akunina [59]3 years ago
3 0
7/8 equals .875 ik this because i am in college
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F=(2xy +z³)i + x³j + 3xz²k find a scalar potential and work done in moving an object in the field from (1,-2,1) to (3,1,4)​
Alex73 [517]

Step-by-step explanation:

Given:

\textbf{F} = (2xy + z^3)\hat{\textbf{i}} + x^3\hat{\textbf{j}} + 3xz^2\hat{\textbf{k}}

This field will have a scalar potential \varphi if it satisfies the condition \nabla \times \textbf{F}=0. While the first x- and y- components of \nabla \times \textbf{F} are satisfied, the z-component doesn't.

(\nabla \times \textbf{F})_z = \left(\dfrac{\partial F_y}{\partial x} - \dfrac{\partial F_x}{\partial y} \right)

\:\:\:\:\:\:\:\:\: = 3x^2 - 2x \ne 0

Therefore the field is nonconservative so it has no scalar potential. We can still calculate the work done by defining the position vector \vec{\textbf{r}} as

\vec{\textbf{r}} = x \hat{\textbf{i}} + y \hat{\textbf{j}} + z \hat{\textbf{k}}

and its differential is

\textbf{d} \vec{\textbf{r}} = dx \hat{\textbf{i}} + dy \hat{\textbf{j}} + dz \hat{\textbf{k}}

The work done then is given by

\displaystyle \oint_c \vec{\textbf{F}} • \textbf{d} \vec{\textbf{r}} = \int ((2xy + z^3)\hat{\textbf{i}} + x^3\hat{\textbf{j}} + 3xz^2\hat{\textbf{k}}) • (dx \hat{\textbf{i}} + dy \hat{\textbf{j}} + dz \hat{\textbf{k}})

\displaystyle = (x^2y + xz^3) + x^3y + xz^3|_{(1, -2, 1)}^{(3, 1, 4)}

= 422

5 0
3 years ago
What is the measure of FEG?
MArishka [77]

Answer:

C. 50 degrees

Step-by-step explanation:

Because 6x + 5x = 110° and x = 10

5×10 = FEG 50°

8 0
3 years ago
I ONLY need help with the tables ONLY! I’LL GIVE BRAINLIEST FOR THE RIGHT ANSWER?! I please include what you did for both tables
neonofarm [45]

Answer:

The first table.

Step-by-step explanation:

Every single time, the x is being multiplied by 3 to get the y, and that means its proportional. Also, the second one is for sure NOT proportional

7 0
3 years ago
A company that offers tubing trips down a river rents tubes for a person to use for $20 and “cooler” tubes to carry food and wat
aivan3 [116]

The group rent 11 river rent tubes and 4 cooler tubes.

Step-by-step explanation:

Rent for river rent tube = $20

Rent for cooler tubes = $12.50

Total spent = $270

Total tubes rented = 15

Let,

x be the number of river rent tube.

y be the number of cooler tubes.

According to given statement;

x+y=15    Eqn 1

20x+12.50y=270    Eqn 2

Multiplying Eqn 1 by 20

20(x+y=15)\\20x+20y=300\ \ \ Eqn\ 3

Subtracting Eqn 2 from Eqn 3

(20x+20y)-(20x+12.50y)=300-270\\20x+20y-20x-12.50y=30\\7.50y=30

Dividing both sides by 7.5

\frac{7.5y}{7.5}=\frac{30}{7.5}\\y=4

Putting y=4 in Eqn 1

x+4=15\\x=15-4\\x=11

The group rent 11 river rent tubes and 4 cooler tubes.

Keywords: linear equations, subtraction

Learn more about linear equations at:

  • brainly.com/question/8520610
  • brainly.com/question/846474

#LearnwithBrainly

6 0
3 years ago
A rectangular swimming pool measures 50 meters in length and 25 meters in width.
GrogVix [38]

Answer:

width = 5cm

length = 10cm

Step-by-step explanation:

1. the ratio is 1:5 so 50 metres in real life is 10 centimetres on paper so length = 10 cm

2. 25 metres in real life is 5 centimetres on paper so width = 5 cm

8 0
3 years ago
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