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1 year ago

Brainliest points whatever you want please

Mathematics

1 answer:

nadya68 [22]1 year ago

4 0

Annual rate of return earned when the share was sold at $50 per share is 20%

Annual rate of return earned when the share was sold at $60 per share is 40%

<h3>How to calculate annual rate of return</h3>

Annual rate of return is given by the formula

let end of the year price = eyp

let beginning of the year price = byp

= {(eyp - byp) / byp} * 100

Annual rate of return at share price of $50 per share

when there is paying of dividends the value is added to the the eyp

eyp = 50 * 100 + 2 * 100 * 5 = 6000

byp = 50 * 100 = 5000

= {(6000 - 5000) / 5000} * 100

= 20%

Annual rate of return at share price of $60 per share

eyp = 60 * 100 + 2 * 100 * 5 = 7000

byp = 50 * 100 = 5000

= {(7000 - 5000) / 5000} * 100

= 40%

Learn more about annual rate of return here:

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Express the system as AX = B; then solve using matrix inverses

Wittaler [7]

Answer with explanation:

1. The given equations are

3x -5 y=2

-x+2 y= 0

⇒The matrix in the form of , AX=B, is

$A=\left[\begin{array}{cc}3&-5\\-1&2\end{array}\right] ,\\\\ X=\left[\begin{array}{c}x&y\end{array}\right],\\\\B=\left[\begin{array}{c}2&0\end{array}\right]$

$\rightarrow X=A^{-1}B\\\\\rightarrow X=\frac{Adj.A}{|A|}\times B$

Adj.A=Transpose of cofactor of Matrix A

$Adj.A=\left[\begin{array}{cc}2&1\\5&3\end{array}\right] ,\\\\ |A|=6-5\\\\|A|=1\\\\\left[\begin{array}{c}x&y\end{array}\right]=\left[\begin{array}{cc}2&5\\1&3\end{array}\right] \times \left[\begin{array}{c}2&0\end{array}\right]\\\\x=4, y=2$

The given equations are

x+y-z=2

x+z=7

2 x +y+z=13

⇒The matrix in the form of , AX=B, is

$A=\left[\begin{array}{ccc}1&1&-1\\1&0&1\\2&1&1\end{array}\right]\\\\ X=\left[\begin{array}{ccc}x\\y\\z\end{array}\right]\\\\B= \left[\begin{array}{ccc}2\\7\\13\end{array}\right]\\\\\rightarrow X=A^{-1}B\\\\\rightarrow X=\frac{Adj.A}{|A|}\times B\\\\a_{11}=-1,a_{12}=1,a_{13}=1,a_{21}=-2,a_{22}=3,a_{23}=1,a_{31}=1,a_{32}=-2,a_{33}=-1\\\\|A|=1\times(0-1)-1\times(1-2)-1\times(1-0)\\\\=-1+1-1\\\\|A|=-1\\\\Adj.A=\left[\begin{array}{ccc}-1&-2&1\\1&3&-2\\1&1&-1\end{array}\right]$

$\frac{Adj.A}{|A|}=\left[\begin{array}{ccc}1&2&-1\\-1&-3&2\\-1&-1&1\end{array}\right]\\\\X=A^{-1}B\\\\\left[\begin{array}{ccc}x\\y\\z\end{array}\right]=\left[\begin{array}{ccc}1&2&-1\\-1&-3&2\\-1&-1&1\end{array}\right]\times\left[\begin{array}{ccc}2\\7\\13\end{array}\right]\\\\x=3,y=3,z=4$

7 0

3 years ago

Morgan's mom wants to borrow $720 to buy a new computer. The store will charge her 8% simple interest for one year. How much wil

Afina-wow [57]

Answer:

$777.60

Step-by-step explanation:

8/100 = 0.08

0.08 * 720 = 57.6

57.6 + 720 = 777.6

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3 years ago

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Consider this cylinder with the given base area and height measures. A cylinder with height of 9 inches and Base B = 12 pi inche

Ipatiy [6.2K]

Answer:

108 pi inches cubed

Step-by-step explanation:

The volume of a cylinder is base area times volume. Since we have our base area of 12 pi, and our height of 9, we have the are as 12* 9 = 108 pi inches cubed. Thus, the answer is D.

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3 years ago

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PQ is bisected at point R by MN. Which of the following I true about point R.

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Answer:

C. R is the midpoint of PQ.

Step-by-step explanation:

Given that segment PQ is bisected at point R by MN.

It means PQ is divided into two parts at point R by the segment MN.

That is, PR = RQ

Hence, R is the midpoint of PQ.

It is not given that the segment MN is bisected by PQ.

So, R need not be the midpoint of MN.

Please refer to the attached figure for better understanding.

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4 years ago

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WILL GIVE BRAINLIEST!!

dexar [7]

Peter reflecting trapezoid ABCD across the y-axis would not change the degree measurement of angle A

The degree measurement of angle A is 115 degrees

<h3>How to determine the degree measurement of angle A?</h3>

From the question, we have:

A = 115 degrees

B = 65 degrees

The transformation is a reflection across the y-axis

Reflection is a rigid transformation; and it does not change the angle measure or side lengths.

After the transformation; we have:

A = 115 degrees

B = 65 degrees

Hence, the degree measurement of angle A is 115 degrees