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madreJ [45]
3 years ago
15

justin was trying to figure out how to write the expression 7 less than 'the double of twenty five. help justin write the expres

sion correctly, and then solve.
Mathematics
2 answers:
Amanda [17]3 years ago
7 0
The double of 25 is (25+25), or (25x25). 7 less would be (25+25) -7. Figure out what 25 + 25 is, then subtract 7 from your answer.
vova2212 [387]3 years ago
7 0
25 x 2 -7 = 43.

Hi! The “7 less than” would immediately go to the back because it is subtracting from something. The double means to multiply the 25 times two. You wouldn’t need parenthesis because of the rules of PEMDAS. 50-7 = 43.

Hope this helps!
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A bank loans ​$2100 to a business at 7​% for 3 months. How much simple interest will the bank​ earn?
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Find the perimeter P of ▱JKLM with vertices J(−3,−2), K(−5,−5), L(1,−5), and M(3,−2). Round your answer to the nearest tenth, if
Bezzdna [24]

Given:

Vertices of JKLM are J(−3,−2), K(−5,−5), L(1,−5), and M(3,−2).

To find:

The perimeter P of a parallelogram JKLM.

Solution:

Distance formula:

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using distance formula, we get

JK=\sqrt{\left(-5-\left(-3\right)\right)^2+\left(-5-\left(-2\right)\right)^2}

JK=\sqrt{\left(-5+3\right)^2+\left(-5+2\right)^2}

JK=\sqrt{\left(-2\right)^2+\left(-3\right)^2}

JK=\sqrt{4+9}

JK=\sqrt{13}

Similarly,

KL=\sqrt{\left(1-\left(-5\right)\right)^2+\left(-5-\left(-5\right)\right)^2}=6

LM=\sqrt{\left(3-1\right)^2+\left(-2-\left(-5\right)\right)^2}=\sqrt{13}

JM=\sqrt{\left(3-\left(-3\right)\right)^2+\left(-2-\left(-2\right)\right)^2}=6

Now, perimeter P of ▱JKLM is

P=JK+KL+LM+JM

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P=2\sqrt{13}+12

P=2(3.61)+12

P=7.22+12

P=19.22

P\approx 19.2

Therefore, the perimeter P of ▱JKLM is 19.2 units.

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