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2 years ago

Please answer correctly !!!!!!!!!!! Will mark brainliest !!!!!!!!!!!!!!

Mathematics

1 answer:

Schach [20]2 years ago

6 0

Answer:

between step 1 and 2 he left off the 5

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1. Simplifying Equation Below please help!!

vichka [17]

Answer: 0

Step-by-step explanation:

In this equation 0/y would equal 0, no matter what y is. 0/y means that there's 0 items out of y items (ex: substitute y with 2, it would be 0/2). Beginning with 1*0 (one times zero) the answer there would be 0. Since we already know that 0/y equals 0, the rest of the equation would be 0 - 0 which would equal to 0. Hope this explanation helps :)

8 0

2 years ago

Read 2 more answers

the sum of two numbers is 48, difference is 14. find the numbersthe sum of two numbers is 48 and their difference is 14 what are

Lady_Fox [76]

The answer is 17 and 31

7 0

2 years ago

Find the measure of each angle indicated. Round to the nearest tenth.

Sladkaya [172]

Answer:

Step-by-step explanation:

So we want to find θ. We are already given the hypotenuse and the side length opposite to θ. Therefore, we can use the trig function sine to find θ.

Recall that:

$\sin(\theta)=opp/hyp$

Plug in 10.2 for the opposite side and 15 for the hypotenuse:

$\sin(\theta)=10.2/15$

Solve for θ. Use a calculator:

$\theta=\sin^{-1}(10.2/15)\\\theta\approx42.8436\textdegree$

The answer is D.

5 0

2 years ago

Select the correct answer,

Inessa05 [86]

Answer:

B. It is too risky to use credit cards online, and online payment services have better security because of the increasing number of hackers that may steal money from your bank account.

Step-by-step explanation:

7 0

3 years ago

Y=x+1 and y=-x-3 in graphing,Substitution,and elemination

marysya [2.9K]

$\left\{\begin{array}{ccc}y=x+1\\y=-x-3\end{array}\right\\\\GRAPHING\ \text{(look at the picture)}\\\\y=x+1\\for\ x=0\to y=0+1=0\to(0,\ 1)\\for\ x=-1\to y=-1+1=0\to(-1,\ 0)\\\\y=-x-3\\for\ x=0\to y=-0-3=-3\to(0,\ -3)\\for\ x=-3\to y=-(-3)-3=0\to(-3,\ 0)\\\\Solution:\ (-2,\ -1)$

$SUBSTITUTION\\\\\left\{\begin{array}{ccc}y=x+1\\y=-x-3\end{array}\right\\\\\text{substitute}\ y=-x-3\ \text{to the first equation}\\\\-x-3=x+1\ \ \ \ |+3\\-x=x+4\ \ \ \ |-x\\-2x=4\ \ \ \ |:(-2)\\x=-2\\\\\text{substitute the value of x to the second equation}\\\\y=-(-2)-3=2-3=-1\\\\Solution:\ (-2,\ -1)$

$ELIMINATION\\\\\underline{+\left\{\begin{array}{ccc}y=x+1\\y=-x-3\end{array}\right}\ \ \ |\text{add both sides of the equations}\\.\ \ \ \ 2y=-2\ \ \ \ |:2\\.\ \ \ \ \ \ y=-1\\\\\text{put the value of y to the first equation}\\\\-1=x+1\ \ \ \ |-1\\x=-2\\\\Solution:\ (-2,\ -1)$

5 0

2 years ago