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mixas84 [53]
3 years ago
15

Please help me with this 30 points

Mathematics
1 answer:
gogolik [260]3 years ago
3 0

Answer:

D

Step-by-step explanation:

For every 1 unit, it goes vertically 1/2

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What is the denominator of the simplified expression? (startfraction 2 n over 6 n + 4 endfraction) (startfraction 3 n + 2 over 3
max2010maxim [7]

n/3n - 2.

The denominator of the given simplified expression is

The given expression is ( 2n/6n + 4 ) ( 3n + 2/ 3n - 2 )

To find the denominator of the simplified expression :

First, simplify the given expression as below ;

( 2n/6n + 4 ) ( 3n + 2/ 3n - 2 )

( 2n/2₍₃ₙ ₊ ₂₎ ( 3n + 2/ 3n - 2 )  ( here by taking the common term 2 outside the factor )

= (n/1) ( 1/ 3n - 2 ) ( here by simplifying the factors )

= n/3n - 2.

Therefore, ( 2n/6n + 4 ) ( 3n + 2/ 3n - 2 ) = n/3n - 2

Therefore the result of the given simplified expression is = n/3n - 2.

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4 0
2 years ago
You are asked to do a study of shelters for abused and battered women to determine the necessary capacity in your city to provid
ohaa [14]

Answer:

Using the normal probability distribution, with a capacity of 350, it is enough for all abused on 90.82% of nights.

274 shelters will be needed.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 250, \sigma = 75

If the city’s shelters have a capacity of 350, will that be enough places for abused women on 95% of all nights?

What is the percentile of 350?

This is the pvalue of Z when X = 350.

Z = \frac{X - \mu}{\sigma}

Z = \frac{250 - 150}{75}

Z = 1.33

Z = 1.33 has a pvalue of 0.9082.

Using the normal probability distribution, with a capacity of 350, it is enough for all abused on 90.82% of nights.

If not, what number of shelter openings will be needed?

The 95th percentile, which is X when Z = 1.645. So

Z = \frac{X - \mu}{\sigma}

1.645 = \frac{X - 150}{75}

X - 150 = 1.645*75

X = 274

274 shelters will be needed.

5 0
3 years ago
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