((10^x)^3)+4=129 subtract 4 from both sides
((10^x)^3)=125 to cancel out the 3rd power, cube root both sides
∛((10^x)^3)=∛125
10^x=5 use logarithms where 10 is the base (cant figure out how to write it in)
log5 = x plug into calculator log5
x=0.69897
None of the offered choices is correct.
f(3) = 0.02·2³ = 0.02·8 = 0.16
f(8) = 0.02·2⁸ = 0.02·256 = 5.12
Then the average rate of change is
... (f(8) - f(3))/(8 - 3) = (5.12 -0.16)/5 = 4.96/5 = 0.992
Answer:
Option A
Step-by-step explanation:
The complete question is attached here
The rate of increase of bacterial population be K
As we know
where Y is the final population. In this case it is 1000
K is the rate of increase of population i.e 3 times per hour
T is the time in hours
Y0 is the initial population = 5
Substituting the given values, we get -
Taking log on both sides, we get -
ln = ln
T = 2.084 hours
hence, option A is correct
Answer:
250-124=126/0.12=1050
answer is 1050 doghnut
Step-by-step explanation:
Answer:
Rotated then reflected.
Step-by-step explanation: