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frutty [35]
3 years ago
9

Elimination -3x-y=2 X-y=2

Mathematics
2 answers:
notsponge [240]3 years ago
8 0

Answer:

x=0, y=-2

Step-by-step explanation:

Given equations are:

\[-3x-y=2\] ---- (1)

\[x-y=2\]     ---- (2)

Subtracting equation 1 from equation 2:

\[(x-y)-(-3x-y) = 2-2\]

\[x-(-3x) = 2-2\]

=> \[x+ 3x = 0\]

=> \[4x = 0\]

=> \[x= 0/4\]

=> \[x=0\]

Substituting the value of x=0 in equation 2:

\[0-y=2\]

=> \[y= -2\]

So the solutions of the given equations by elimination are : x=0, y=-2

Validating the solution by substituting in equation 1:

Left Hand Side : \[-3 * 0 - (-2) = 0 +2 = 2\]

Right Hand Side : 2

Since the two sides are equal, the solution is valid.

hodyreva [135]3 years ago
4 0

Answer:

x=0

y=-2

Step-by-step explanation:

-3x-y=2

x-y=2

subtract

-3x-y-x+y=2-2

-4x=0

x=0

0-y=2

y=-2

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\begin{gathered} R^{\prime}(200)=\frac{125}{\sqrt{200}}-5 \\ =\frac{125}{10\sqrt{2}}-5 \\ =8.8388-5 \\ =3.8388 \\ =3.84 \end{gathered}

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