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makkiz [27]
3 years ago
8

What is the distance between the two points (6, -2) and (4,6)?

Mathematics
2 answers:
Lynna [10]3 years ago
6 0
The distance is 8.246 units.
That is because if we make a right triangle with these points and use the pythagorean theorem, we will get the diagonal's length.
AlexFokin [52]3 years ago
3 0
Use the distance formula;

d = √(x₂ - x₁)² + (y₂ - y₁)²     (6, -2),  (4, 6)

d = √(4 - 6)² + (6 - (-2)²

d = √(-2)² + (8)²

d = √4 + 64

d = √68      or  2√17 or 8.25

hope this helps, God bless!
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51 hours

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$22.5 x 11 = $247.5

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Solve for x: 3/3x + 1/x+4 = 10/7x
Mekhanik [1.2K]
Given,

3/3x + 1/(x + 4) = 10/7x

1/x + 1/(x+4) = 10/7x

Because the first term on LHS has 'x' in the denominator and the second term in the LHS has '(x + 4)' in the denominator. So to get a common denominator, multiply and divide the first term with '(x + 4)' and the second term with 'x' as shown below

{(1/x)(x + 4)/(x + 4)} + {(1/(x + 4))(x/x)} = 10/7x

{(1(x + 4))/(x(x + 4))} + {(1x)/(x(x + 4))} = 10/7x

Now the common denominator for both terms is (x(x + 4)); so combining the numerators, we get,

{1(x + 4) + 1x} / {x(x + 4)} = 10/7x

(x + 4 + 1x) / (x(x + 4)) = 10/7x

(2x + 4) / (x(x + 4)) = 10/7x

In order to have the same denominator for both LHS and RHS, multiply and divide the LHS by '7' and the RHS by '(x + 4)'

{(2x+4) / (x(x + 4))} (7 / 7) = (10 / 7x) {(x + 4) / (x + 4)}

(14x + 28) / (7x(x + 4)) = (10x + 40) / (7x(x + 4))

Now both LHS and RHS have the same denominator. These can be cancelled. 

∴14x + 28 = 10x + 40
14x - 10x = 40 - 28
4x = 12
x = 12/4

∴x = 3



8 0
3 years ago
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