What is 5/8 divided by 20
2 answers:
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Answer:
Explanation:
<u>1. Given vector:</u>
- length: 4.00 mm = magnitude of the vector
- angle: 23.5º north of east = 23.5º from the x-axys (counterclockwise)
<u>2. y-component</u>
The y-component may be determined using the sine ratio, the angle from the x-axys (counterclockwise direction), and the magnitude of the vector.
- sine (23.5º) = y-component / magnitude
- y-component = magnitude × sine (23.5º) = 4.00 mm × sine (23.5º) = 1.59 mm.
I'm here buddy,
so, let's take the value of the two bags with equal weight as x.
= x + x + (x + ) =
= 3x + =
= 3x = -
( let's take the LCM of 4 and 5 = 20
= 3x = -
= 3x =
= x = ÷
=
×
=
So, the weight of the equal bags are and the weight of the third bag ( heavy one ) is
+
=
+
=
1st bag = kg
2nd bag = kg
3rd bag = kg
Hope it helps...