<img src="https://tex.z-dn.net/?f=%28x%2B3%29%28x%2B5%29%3D0" id="TexFormula1" title="(x+3)(x+5)=0" alt="(x+3)(x+5)=0" align="ab

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3 years ago

6

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1 answer:

Rudiy273 years ago

6 0

Answer:

X= -3 and X= -5

Step-by-step explanation:

(x+3)(x+5)= 0

-Set factors equal to 0

X+3 = 0 X+5 = 0

(Move the 3 on the other side of the equal sign just by subtracting it from zero. After that, do the same for 5)

And you get: X= -3 and X= -5

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Lcm can you help me learn the process of lcm

Svetllana [295]

Say you had the numbers 3 and 4. The LCM is the lowest number that both 3 and 4 will factor into.
The multiples of 4: 4,8,12,16,20,24
The multiples of 3: 3,6,9,12,15,18,21,24
They both factor into 12 and 24 but 12 is the least common multiple or smallest number they both go into :) I really hope this helps!! :)

3 0

3 years ago

lawyer [7]

The group paid $ 5250 at first city and $ 6250 at second city

<u>Solution:</u>

Let x = the charge in 1st city before taxes

Let y = the charge in 2nd city before taxes

The hotel charge before tax in the second city was $1000 higher than in the first

Then the charge at the second hotel before tax will be x + 1000

y = x + 1000 ----- eqn 1

The tax in the first city was 8.5% and the tax in the second city was 5.5%

The total hotel tax paid for the two cities was $790

<em><u>Therefore, a equation is framed as:</u></em>

8.5 % of x + 5.5 % of y = 790

$\frac{8.5}{100} \times x + \frac{5.5}{100} \times y = 790$

0.085x + 0.055y = 790 ------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

<em><u>Substitute eqn 1 in eqn 2</u></em>

0.085x + 0.055(x + 1000) = 790

0.085x + 0.055x + 55 = 790

0.14x = 790 - 55

0.14x = 735

<h3>x = 5250</h3>

<em><u>Substitute x = 5250 in eqn 1</u></em>

y = 5250 + 1000

<h3>y = 6250</h3>

Thus the group paid $ 5250 at first city and $ 6250 at second city

8 0

3 years ago

The table displays the frequency of scores for a calculus class on an exam. The mean of the exam scores is 3.5. Score 1 2 3 4 5

vladimir1956 [14]

Answer:

f=11

Mode=4

Median=4

Explanation:

We are given that

a.Mean of the exam score, $\bar x$ =3.5

Score(x) frequency C.F

1 1 1

2 3 4

3 f 15(4+f=4+11)

4 13 28

5 4 32

$\sum f_i=1+3+f+13+4=21+f$

$\sum f_ix_i=1(1)+2(3)+3(f)+4(13)+5(4)=1+6+3f+52+20=79+3f$

$(\bar x)=\frac{\sum f_ix_i}{\sum f_i}$

Using the formula

$3.5=\frac{79+3f}{21+f}$

$73.5+3.5f=79+3f$

$3.5f-3f=79-73.5$

$0.5f=5.5$

$f=\frac{5.5}{0.5}=11$

b.Mode:The number which is repeat most times .

4 repeat most times

Hence, mode of all exam scores=4

N=32

N is even

$Median=\frac{(\frac{n}{2})^{th}+(\frac{n}{2}+1)^{th}}{2}$

Median= $\frac{16th+17th}{2}=\frac{4+4}{2}=\frac{8}{2}=4$

7 0

3 years ago

Find the volume of this figure. round your answer to the nearest hundredth. if necessary

Shalnov [3]

V=πr^2 h/3
Replace the given values in place of the expression

4 0

2 years ago

Nvm i have a new question i need to know if the answer is correct

insens350 [35]

<em>multiply the numbers.</em>

4 x 6 + y = 20

<em>move constant (24) to the right side and change its sign.</em>

24 + y = 20

<em>calculate the difference and you get the answer.</em>

y = 20 - 24

y = -4

So the value of y is -4.

5 0

3 years ago