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3 years ago

15

The graph of a linear function passes through the point (1, 1) and has a slope of -3. What is the equation of the function in sl

ope-intercept form?

1 answer:

Zigmanuir [339]3 years ago

5 0

Use the point-slope formula
y-y1=m(x-x1)
y-1=-3(x-1)
y-1=-3x+3
y=-3x+4

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Through: (-1,4), perpendicular to y = x

Law Incorporation [45]

Answer:

y = -x + 3

Step-by-step explanation:

I graphed the equation on the graph below to show you that it goes through (-1,4) and is perpendicular to y = x.

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3 years ago

Write an inequality that would include the point (3,78), (0,312), (5,10) to be part of the solution.

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Answer:

We want to write an inequality with the points (3, 78), (0, 312) and (5, 10) as solutions.

Then the set of the x-values is {0, 3, 5}

The set of the y-values is {10. 78. 312}

So if we wrote an inequality like:

y > 5

It would include all these solutions, because:

10 > 5

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312 > 5

And this has no restriction on the x-variable, so all the x-value range can be a solution, meaning that the points (3, 78), (0, 312) and (5, 10) are solutions to that inequality.

Another one (also trivial) can be:

x < 9

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3 < 9

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3 years ago

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Which equation has a graph that is a parabola with a vertex at (5,3)?

lara [203]

Answer:

y = (x -5)² + 3.

Step-by-step explanation:

Given : parabola with a vertex at (5,3).

To find : Which equation has a graph that is a parabola.

Solution : We have given vertex at (5,3).

Vertex form of parabola : y = (x -h)² + k .

Where, (h ,k ) vertex .

Plug h = 5 , k= 3 in vertex form of parabola.

Equation :y = (x -5)² + 3.

Therefore, y = (x -5)² + 3.

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3 years ago