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marishachu [46]

2 years ago

14

Please help me or i will fail

2 answers:

34kurt2 years ago

8 0

The answer is A, because if he took the % of how many people attended the last game, that wouldn't be a sample. If he took a sample of the friends of the players, they don't necessarily have to be a part of the town. If he took a sample of the people who are on sports teams, that would just be dumb. He wanted to know how many people from the TOWN would attend. SO if he took a random sample of the people from the TOWN, he would have the most accurate answer.

omeli [17]2 years ago

6 0

A I think is the right answer

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Vladimir [108]

To graph the equations, rewrite the equations written in standard form to slope-intercept form of the equation.

$y=mx+b\\\\ 2x-3y=6\\ 2x+y=-10 \\\\3y= 2x- 6\ \ / :3\\ y=-2x-10 \\\\y= \frac{2}{3}x- 2 \\ y=-2x-10$

$Answer : \\ \\The \ lines \ intersect \ when \ x = -3 \ and \ y = -4$

5 0

2 years ago

An Airliner has a capacity for 300 passengers. If the company overbook a flight with 320 passengers, What is the probability tha

TEA [102]

Answer:

The probability is $P(X >300 ) = 0.97219$

Step-by-step explanation:

From the question we are told that

The capacity of an Airliner is k = 300 passengers

The sample size n = 320 passengers

The probability the a randomly selected passenger shows up on to the airport

$p = 0.96$

Generally the mean is mathematically represented as

$\mu = n* p$

=> $\mu = 320 * 0.96$

=> $\mu = 307.2$

Generally the standard deviation is

$\sigma = \sqrt{n * p * (1 -p ) }$

=> $\sigma = \sqrt{320 * 0.96 * (1 -0.96 ) }$

=> $\sigma =3.50$

Applying Normal approximation of binomial distribution

Generally the probability that there will not be enough seats to accommodate all passengers is mathematically represented as

$P(X > k ) = P( \frac{ X -\mu }{\sigma } > \frac{k - \mu}{\sigma } )$

Here $\frac{ X -\mu }{\sigma } =Z (The \ standardized \ value \ of \ X )$

=> $P(X >300 ) = P(Z > \frac{300 - 307.2}{3.50} )$

Now applying continuity correction we have

$P(X >300 ) = P(Z > \frac{[300+0.5] - 307.2}{3.50} )$

=> $P(X >300 ) = P(Z > \frac{[300.5] - 307.2}{3.50} )$

=> $P(X >300 ) = P(Z > -1.914 )$

From the z-table

$P(Z > -1.914 ) = 0.97219$

So

$P(X >300 ) = 0.97219$

8 0

2 years ago

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Genrish500 [490]

You need to add a -1

We can find this by setting up the equation like so

x + (-6) + 12 + 15 / 4 = 5

x + 21 = 20

x = 20 -21

x = -1

Now if we insert -1 where x is located in the equation, you will get a means of 5

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Alex_Xolod [135]

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see attached picture:

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Simora [160]

Answer:

the answer is B

Step-by-step explanation:

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2 years ago