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3 years ago

The equation v(x)=32500(0.92)^x how much more is the truck worth after two years than after three years

Mathematics

1 answer:

Lyrx [107]3 years ago

6 0

Answer:

the difference: $2,192.64

Step-by-step explanation:

After 1 year, the truck has lost 8% of its value: v(x) = $32,500(0.92)^1, or

$29,900.

After 2 years, v(x) = $32,500(0.92)^2, or $27,500. Finally, after 3 years,

v(x) = $32,500(0.92)^3 = $25,307.36.

Subtracting $25,307.36 (the value after 3 years) from $27,500 (the value after 2 years) yields the difference: $2,192.64

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3 years ago

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Answer:−3+3=−4

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−3+3=−4

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Step 2: Write the two new equations

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Step-by-step explanation:

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