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-BARSIC- [3]
4 years ago
11

Find the common ratio in a geometric sequence where the first term is 2/5 and the third term is 1/10

Mathematics
1 answer:
STALIN [3.7K]4 years ago
3 0
GP is given by = arⁿ⁻¹

First term of GP =  2/5,    a = 2/5      ......(i)

Third term = 1/10,             ar² = 1/10    ......(ii)

(ii) ÷ (i)

ar² ÷ a = (1/10) ÷ (2/5)

r²  =    1/10 × 5/2

r²  =  1/4            Take square root of both sides

r = √(1/4)

r = 1/2.

Common ratio = 1/2.
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