Question

If s(x)=x-7 and t(x)=4x^2-x+3 which expression is equivalent to (t•s)(x)?

Answer 1

Hello :
s(x)=x-7 and t(x)=4x²-x+3
(t•s)(x) = t(s(x)) = t(x-7) = 4(x-7)²-(x-7) +3
(t•s)(x) = 4(x-7)²-x+7+3

Answer 2

Answer:  (B) $4(x-7)^2-(x-7)+3.$

Step-by-step explanation:  We are given the following two functions :

$s(x)=x-7,\\\\t(x)=4x^2-x+3.$

We are to find the expression that is equivalent to $(t.s)(x).$

We know that

for any two functions f(x) and g(x), we have

$(f.g)(x)=f(g(x)).$

Therefore, we get

$(t.s)(x)\\\\=t(s(x))\\\\=t(x-7)\\\\=4(x-7)^2-(x-7)+3.$

Thus, $(t.s)(x)$ is equivalent to $4(x-7)^2-(x-7)+3.$

Option (B) is CORRECT.