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3 years ago

M'NO'P has vertices at

Mathematics

1 answer:

Yuliya22 [10]3 years ago

3 0

Answer:

Dilation(origin, 2/3)

Step-by-step explanation:

The coordinate values of the image are 3/4.5 = 2/3 times those of the pre-image.

Different authors write these dilations different ways. Essentially, it is ...

transformation(center, scale factor) = Dilation(origin, 2/3)

Your required format likely will vary.

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The APR of Percy’s savings account is 4.4%, and interest is compounded monthly. If the principal in Percy’s savings account were

lutik1710 [3]

Answer:$11,389.39

Step-by-step explanation:

(Apex)

8 0

3 years ago

Compare the dimensions of the prisms. How many times greater is the surface area of the green prism than the surface area of the

vodomira [7]

Answer:

the green prisim is 5.59 or 5 times bigger!

Step-by-step explanation:

The surface area of the green prisim is 850 and the surface area of the blue one is 150 and 850 divided by 150 is 5.59!

5 0

3 years ago

Please help what is the equation

Elanso [62]

let us take any two points here (5,20) and (7,30)

now let us use slope formula to get its slope

$slope=\frac{y2-y1}{x2-x1}$

$slope=\frac{30-20}{7-5}$

slope =5

now let us use one coordinate (say (5,20)) and slope to get the y intercept

20= 5*5 +b

b=-5

plugging the values of b and m in the given equation we get

y=5x-5

or c=5m-5

7 0

3 years ago

Which statement describes if there is an extraneous solution to the equation √x-3 = x-5? A. there are no solutions to the equati

Brrunno [24]

Remember that an extraneous solution of an equation, is the solution that emerges from solving the equation but is not a valid solution.

Lets solve our equation to find out what is the extraneous solution:
 $\sqrt{x-3} =x-5$
$(\sqrt{x-3})^2 =(x-5)^2$
$x-3=x^2-10x+25$
$x^2-11x+28=0$
$(x-4)(x-7)=0$
$x-4=0$ and $x-7=0$
$x=4$ and $x=7$

So, the solutions of our equation are $x=4$ and $x=7$ . Lets replace each solution in our original equation to check if they are valid solutions:
- For $x=7$
$\sqrt{x-3} =x-5$
$\sqrt{7-3} =7-5$
$\sqrt{4} =2$
$2=2$
We can conclude that 7 is a valid solution of the equation.

- For $x=4$
$\sqrt{x-3} =x-5$
$\sqrt{4-3} =4-5$
$\sqrt{1} =1$
$1 \neq 1$
We can conclude that 4 is not a valid solution of the equation; therefore, 4 is a extraneous solution.

We can conclude that the correct answer is: D. the extraneous solution is x = 4

7 0

3 years ago

A jar contains 2 red and 4 blue marbles. A marble is drawn from the jar. What is the probability that a red marble will be drawn

allsm [11]

Salutations!

A jar contains 2 red and 4 blue marbles. A marble is drawn from the jar. What is the probability that a red marble will be drawn?

So lets solve this!

Probability is an event of chance; an occurrence of chance.

The probability that a red marble will be drawn is 2/6

Simply 2/6 which is 1/3

Thus, your answer is option C.

Hope I helped :D

5 0

3 years ago

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