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joja [24]
3 years ago
14

Assume you purchased a car for $2,300 and sold it one week later for $3,100. How much did your net worth change, if at all?

Mathematics
1 answer:
Natali5045456 [20]3 years ago
4 0

Answer:

My net wroth would have changed by $800

Step-by-step explanation:

Because $3,100 - $2,300 = $800

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Goryan [66]

12) the radius is 15 so with the equation (3.14)*r^2, we get (3.14)(15^2)=706.5

13) true, true (if x=4), true

14) y=0.75x+4.50, $8.25

7 0
3 years ago
Jimmy is selling used books at a yard sale. A customer buys 9 books at a cost of $0.75 each and pays with a $20.00 bill. Jimmy m
never [62]
C= 20-0.75x
c= 20-0.75(9)
c= 20-6.75
c= 13.25

Here c is the amount of change and x is the number of books bought.

The customer's change will be $13.25
3 0
3 years ago
Read 2 more answers
Suppose brine containing 0.2 kg of salt per liter runs into a tank initially filled with 500 L of water containing 5 kg of salt.
Oliga [24]

Answer:

(a) 0.288 kg/liter

(b) 0.061408 kg/liter

Step-by-step explanation:

(a) The mass of salt entering the tank per minute, x = 0.2 kg/L × 5 L/minute = 1 kg/minute

The mass of salt exiting the tank per minute = 5 × (5 + x)/500

The increase per minute, Δ/dt, in the mass of salt in the tank is given as follows;

Δ/dt = x - 5 × (5 + x)/500

The increase, in mass, Δ, after an increase in time, dt, is therefore;

Δ = (x - 5 × (5 + x)/500)·dt

Integrating with a graphing calculator, with limits 0, 10, gives;

Δ = (99·x - 5)/10

Substituting x = 1 gives

(99 × 1 - 5)/10 = 9.4 kg

The concentration of the salt and water in the tank after 10 minutes = (Initial mass of salt in the tank + Increase in the mass of the salt in the tank)/(Volume of the tank)

∴ The concentration of the salt and water in the tank after 10 minutes =  (5 + 9.4)/500 = (14.4)/500 = 0.288

The concentration of the salt and water in the tank after 10 minutes = 0.288 kg/liter

(b) With the added leak, we now have;

Δ/dt = x - 6 × (14.4 + x)/500

Δ = x - 6 × (14.4 + x)/500·dt

Integrating with a graphing calculator, with limits 0, 20, gives;

Δ = 19.76·x -3.456 = 16.304

Where x = 1

The increase in mass after an increase in = 16.304 kg

The total mass = 16.304 + 14.4 = 30.704 kg

The concentration of the salt in the tank then becomes;

Concentration = 30.704/500 = 0.061408 kg/liter.

6 0
3 years ago
Which expression is equivalent to 3m+1-m?
Lisa [10]

Answer:

option  (a) is correct.

2 + m - 1 + m is an equivalent expression  to the given expression  3m+1-m

Step-by-step explanation:

 Given expression  3m+1-m

We have to choose an equivalent expression from given options.

Equivalent expression are those expression that looks different but are same.

Like 4+2 = 6  and 3+ 3 = 6

Both have same value but looks differently.

Like terms are term having same variable with same degree.

Consider the given expression  3m+1-m

Simplify by adding like terms,

3m + 1 - m = (3-1) m + 1

Thus, (3-1) m + 1  = 2m + 1

Also 2m + 1 can be written as m + m + 2 - 1

Thus, option  (a) is correct.

6 0
3 years ago
Read 2 more answers
What positive number is left of 1 ( 0 is neutral)
kkurt [141]

Answer:

any number between 0 and 1

Step-by-step explanation:

This includes decimals.

8 0
3 years ago
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