Answer:
a. Weekly Gross pay:
= 9.50 * 20
= $190
b. Federal tax withheld:
= 10% * 190
= $19
c. FICA Tax withheld:
= 5.65% * 190
= $10.74
d. State tax withheld:
= 5% * 190
= $9.50
e. Weekly net pay
= Gross pay - taxes
= 190 - 19 - 10.74 - 9.50
= $150.76
f. Percentage withheld for taxes:
= (19 + 10.74 + 9.50) / 190 * 100%
= 20.7%
We'll use variables to represent the speeds of the eastbound and westbound trains.
x will represent the speed of the eastbound train.
y will represent the speed of the westbound train.
The eastbound train is 16 mph faster than the westbound train. An equation can be made from this:

Subtraction is used, because it represents the difference in distances between the two trains if they travel the same direction.
After 4 hours, the trains are 800 miles apart. An equation can be made from this:

Addition is used, because the trains are heading in opposite directions, which means their distances from the starting point are added together.
Set the two equations up vertically:


We will use elimination to solve for x.
Multiply the entire first equation by 4 so that the coefficients for y will be opposite numbers:



Combine the two equations together to cancel out y:

Divide both sides by 8 to get x by itself:

The speed of the eastbound train is
108 mph.
Answer:
Step-by-step explanation:
Part 1:
Let
Q₁ = Amount of the drug in the body after the first dose.
Q₂ = 250 mg
As we know that after 12 hours about 4% of the drug is still present in the body.
For Q₂,
we get:
Q₂ = 4% of Q₁ + 250
= (0.04 × 250) + 250
= 10 + 250
= 260 mg
Therefore, after the second dose, 260 mg of the drug is present in the body.
Now, for Q₃ :
We get;
Q₃ = 4% of Q2 + 250
= 0.04 × 260 + 250
= 10.4 + 250
= 260.4
For Q₄,
We get;
Q₄ = 4% of Q₃ + 250
= 0.04 × 260.4 + 250
= 10.416 + 250
= 260.416
Part 2:
To find out how large that amount is, we have to find Q₄₀.
Using the similar pattern
for Q₄₀,
We get;
Q₄₀ = 250 + 250 × (0.04)¹ + 250 × (0.04)² + 250 × (0.04)³⁹
Taking 250 as common;
Q₄₀ = 250 (1 + 0.04 + 0.042 + ⋯ + 0.0439)
= 2501 − 0.04401 − 0.04
Q₄₀ = 260.4167
Hence, The greatest amount of antibiotics in Susan’s body is 260.4167 mg.
Part 3:
From the previous 2 components of the matter, we all know that the best quantity of the antibiotic in Susan's body is regarding 260.4167 mg and it'll occur right once she has taken the last dose. However, we have a tendency to see that already once the fourth dose she had 260.416 mg of the drug in her system, that is simply insignificantly smaller. thus we will say that beginning on the second day of treatment, double every day there'll be regarding 260.416 mg of the antibiotic in her body. Over the course of the subsequent twelve hours {the quantity|the quantity|the number} of the drug can decrease to 4% of the most amount, that is 10.4166 mg. Then the cycle can repeat.
Because there are two variables in this equation, you cannot solve for answers. However, I'll assume that you want to get this into slope intercept form as that is the most common way to graph these. The answer in that case is y = 2x - 2
<span>1/2 (y-3)= 1/2 + (x-3) ---> Start by multiplying both sides by 2
(y - 3) = 1 + 2x - 6 ---> now add 3 to each side
y = 3 + 1 + 2x - 6 ----> now simplify like terms.
y = 2x - 2 </span>