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blagie [28]
2 years ago
10

An ordinary (falr) dle is a cube with the numbers 1 through 6 on the sides (represented by painted spots). Imagine that such a d

le is rolled twice in succession
and that the face values of the two rolls are added together. This sum is recorded as the outcome of a single trial of a random experiment.
Compute the probability of each of the following events.
Event A: The sum is greater than 8.
Event B: The sum is divisible by 5.
Write your answers as fractions.
(a) P(X) =

(b) P(B) =
Mathematics
1 answer:
ddd [48]2 years ago
6 0

By finding the number of outcomes that meet each criteria, we will see that the probabilities are:

  • A) P = 0.25
  • B) P = 7/36 = 0.194

<h3>How to find the probability?</h3>

We know that the fair die has 6 outcomes, so if we roll it twice, there are a total of:

6*6 = 36 outcomes.

To find the probability of getting a given event, we need to find the number of outcomes that make the event true.

A) The sum is greater than 8.

The outcomes that make this true are:

first roll    second roll     sum

 4                   5                 9

 4                   6                 10

5                     5                10

5                    6                 11

6                     3                 9

6                    4                 10

6                     5                11

6                     6                  12

3                     6                   9

So there are 9 outcomes whose sum is greater than 8, so the probability to getting this event is:

P = 9/36 = 0.25

B) The sum is divisible by 5.

The sum must be 5 or 10, the outcomes that give that are:

first roll    second roll     sum

   1                   4                 5

   2                  3                 5

   3                  2                 5

   1                   4                 5

   4                   6                10

  5                    5                10

   6                   4                 10

There are 7 outcomes, so the probability is:

P = 7/36 = 0.194

If you want to learn more about probability, you can read:

brainly.com/question/251701

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Before ordering food for a company barbecue the president took a poll. She asked people if they would eat the ribs, hamburgers,
Vinvika [58]

Answer:

The complete question is as shown in the attached figure 1

The Venn diagram is the attached figure 2

Let: R⇒ribs , H⇒hamburgers  and  C⇒corn

People would eat all three = 53

People would eat only R and H = 56 - 53 = 3

People would eat only C and H = 54 - 53 = 1

People would eat only R and C = 55 - 53 = 2

People would eat only H = 60 - (53+3+1) = 60 - 57 = 3

People would eat only R = 59 - (53+3+2) = 59 - 58 = 1

People would eat only C = 56 - (53+1+2) = 0

See Vinn diagram.

=========================================================

a. How many people did not want any of these foods?

people did not want any of these foods = 64 - (53+3+1+2+3+1) = 1

b. How many people would eat ribs but not corn?

people would eat ribs but not corn = 1+3 = 4

c. How many people would eat something as long as it was not a hamburger?

people would eat something as long as it was not a hamburger= 1+2 = 3

d. How many people would eat only corn?

people would eat only corn = 0

e. How many people would eat exactly two foods?

people would eat exactly two foods = 1 + 2 + 1

6 0
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Answer:

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Step-by-step explanation:

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