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Neporo4naja [7]
3 years ago
10

Which equation can be solved to find one of the missing side lengths in the triangle? cos(60o) = cos(60o) = cos(60o) = cos(60o)

=
Mathematics
1 answer:
miv72 [106K]3 years ago
6 0
The answer is:
D)  cos(60°) = a/12
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How do divide 9.54 by 1.8
salantis [7]
Move  the decimal points of both 1.8 and 9.54 to the right by 2 decimal places.and then divide like normal if the # doesn't go input a point and a 0 the answer is .0.1886 hoped I made sense

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5 0
3 years ago
Read 2 more answers
Make the eqaution equal 4,416 for alot of points
irga5000 [103]

Answer:

2 *( 3+7-9) =(1+5) - ( 8 -4 )

Step-by-step explanation:

2 _( 3_7_9) = (1_ 5) _ ( 8 _4 )

I just started playing with things

2 *( 3+7-9) = (1_5 ) _ ( 8 _4 )

2 * (10-9)

2*1

So the left side is 2

Now to make the right side 2

(1+5) - ( 8 -4 )

6 - 4

2

4 0
2 years ago
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12. If n(A) = 14, n(B) = 15, and n(<br>AB) = 6, then n(AUB) is<br>​
motikmotik

Answer:

given n(A) = 14

n(B) = 15

n(A∩B ) = 15

Step-by-step explanation:

now we know that ,n(AUB) = n(A)+n(B)-n(A∩B)

n(AUB) = 14+15-6 = 23.Answer

3 0
2 years ago
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Mr. Corpulence decides to go on a diet where he will lose 4 pounds a month he now weighs 288 pounds
quester [9]

Answer:

y=-4x+288

Step-by-step explanation:

every month he loses 4 lbs starting from his weight is at now

7 0
3 years ago
Al sumar fracciones con igual denominador, debemos sumar numerador con numerador y denominador con denominador. Verdadero o fals
Ahat [919]

Answer:

La respuesta es falso.  

Step-by-step explanation:

La respuesta es falso.  

Cuando se suman fraccciones con igual denominador, se suman los numeradores (numerador con numerador) y se deja el mismo denominador (el cual es común en ambos). Por ejemplo, la suma de 1/5 + 3/5 da como resultado:    

\frac{1}{5} + \frac{3}{5} = \frac{1 + 3}{5} = \frac{4}{5}

En el caso de fracciones con diferentes denominadores, tampoco se suma numerador con numerador y denominador con denominador. En ese caso se debe encontrar el mínimo común múltiplo.

 

Por lo tanto, la respuesta es falso.

Espero que te sea de utilidad!

7 0
2 years ago
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