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insens350 [35]
3 years ago
6

Evaluate the equation.d – 4.12 = 12.8

Mathematics
1 answer:
xxMikexx [17]3 years ago
5 0
I think its 16.16 as the answer

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Witch value of x makes the equation x + 7 = 21 true ?
Shkiper50 [21]

Answer:

x=14

Step-by-step explanation:

x+7=21

x=14

5 0
3 years ago
PLEASE HELP 100 POINTS!!
tresset_1 [31]

y = x^2 + 5x -3

y-x =2

Replace y in the second equation with the first one:

x^2 + 5x -3 - x = 2

Simplify by combining like terms:

x^2 + 4x -3 = 2

Subtract 2 from both sides:

x^2 + 4x -5 = 0

Fctor the polynomial:

(x-1) (x+5) = 0

Solve for both X's:

x = 1 and x = -5

Now replace x in the second equation with both value and solve for y:

y -1 =2, y = 3

y - -5 =2, y +5 = 2, y = -3

Now combine the sets of answers:

(1,3) and (-5,-3)

3 0
3 years ago
Read 2 more answers
What is 4/4+4/9= or 4/9+7/6=
butalik [34]
78
Years ago he had a lot to say he had a great day he was the first man I was ever going for the first one I was never gonna get a
6 0
3 years ago
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Find the greatest possible error for each measurement.<br> 12.3 L
melisa1 [442]

Answer:

the GPE is 1/2 the unit of measure used to make the measurement or you say 1/2 the most precise unit

12.3 L has 0.1 as the most precise unit of measure, so 1/2 of 0.1 is 0.05 L which is c. above

look at it this way: 12.3 can be any number between 12.25 and 12.34 rounded to the nearest tenth

any number from 12.25 to 12.34 rounded to the nearest tenth gives you 12.3, so the GPE that you can possibly make is 0.05; if the number was 12.24 it would round down to 12.2 not up to 12.3 and if the number was 12.35 it would round up to 12.4 not round down to 12.3, so again the greatest possible error that you can make is 0.05

6 0
2 years ago
Find the direction cosines and direction angles of the vector. (Give the direction angles correct to the nearest degree.) 5, 1,
Dahasolnce [82]

Answer:

The direction cosines are:

\frac{5}{\sqrt{42} }, \frac{1}{\sqrt{42} }  and  \frac{4}{\sqrt{42} }  with respect to the x, y and z axes respectively.

The direction angles are:

40°,  81° and  52° with respect to the x, y and z axes respectively.

Step-by-step explanation:

For a given vector a = ai + aj + ak, its direction cosines are the cosines of the angles which it makes with the x, y and z axes.

If a makes angles α, β, and γ (which are the direction angles) with the x, y and z axes respectively, then its direction cosines are: cos α, cos β and cos γ in the x, y and z axes respectively.

Where;

cos α = \frac{a . i}{|a| . |i|}               ---------------------(i)

cos β = \frac{a.j}{|a||j|}               ---------------------(ii)

cos γ = \frac{a.k}{|a|.|k|}             ----------------------(iii)

<em>And from these we can get the direction angles as follows;</em>

α =  cos⁻¹ ( \frac{a . i}{|a| . |i|} )

β = cos⁻¹ ( \frac{a.j}{|a||j|} )

γ = cos⁻¹ ( \frac{a.k}{|a|.|k|} )

Now to the question:

Let the given vector be

a = 5i + j + 4k

a . i =  (5i + j + 4k) . (i)

a . i = 5         [a.i <em>is just the x component of the vector</em>]

a . j = 1            [<em>the y component of the vector</em>]

a . k = 4          [<em>the z component of the vector</em>]

<em>Also</em>

|a|. |i| = |a|. |j| = |a|. |k| = |a|           [since |i| = |j| = |k| = 1]

|a| = \sqrt{5^2 + 1^2 + 4^2}

|a| = \sqrt{25 + 1 + 16}

|a| = \sqrt{42}

Now substitute these values into equations (i) - (iii) to get the direction cosines. i.e

cos α = \frac{5}{\sqrt{42} }

cos β =  \frac{1}{\sqrt{42} }              

cos γ =  \frac{4}{\sqrt{42} }

From the value, now find the direction angles as follows;

α =  cos⁻¹ ( \frac{a . i}{|a| . |i|} )

α =  cos⁻¹ ( \frac{5}{\sqrt{42} } )

α =  cos⁻¹ (\frac{5}{6.481} )

α =  cos⁻¹ (0.7715)

α = 39.51

α = 40°

β = cos⁻¹ ( \frac{a.j}{|a||j|} )

β = cos⁻¹ ( \frac{1}{\sqrt{42} } )

β = cos⁻¹ ( \frac{1}{6.481 } )

β = cos⁻¹ ( 0.1543 )

β = 81.12

β = 81°

γ = cos⁻¹ ( \frac{a.k}{|a|.|k|} )

γ = cos⁻¹ (\frac{4}{\sqrt{42} })

γ = cos⁻¹ (\frac{4}{6.481})

γ = cos⁻¹ (0.6172)

γ = 51.89

γ = 52°

<u>Conclusion:</u>

The direction cosines are:

\frac{5}{\sqrt{42} }, \frac{1}{\sqrt{42} }  and  \frac{4}{\sqrt{42} }  with respect to the x, y and z axes respectively.

The direction angles are:

40°,  81° and  52° with respect to the x, y and z axes respectively.

3 0
3 years ago
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